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3 years ago

If 2.00 moles of H₂ and 1.55 moles of O₂ react how many moles of H₂O can be produced in the reaction below?

Chemistry

1 answer:

jekas [21]3 years ago

5 0

Answer:

2 mol H₂O

Explanation:

With the reaction,

2H₂(g) + O₂(g) → 2 H₂O(g)

1.55 moles of O₂ would react completely with ( 2*1.55 ) 3.1 moles of H₂. There are not as many moles of H₂, thus H₂ is the limiting reactant.

Now we calculate the moles of H₂O produced, starting from the moles of limiting reactant:

2.00 mol H₂ * $\frac{2molH_2O}{2mol H_2}$ = 2 mol H₂O

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v = sqt(TL/m)

Where

density = mass/length

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