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3 years ago

How many atoms are in 3.75 moles of Fe

Chemistry

1 answer:

denis23 [38]3 years ago

6 0

Answer:

2.26 × 10²⁴ atoms of Fe

Explanation:

To calculate the amount of atoms of a substance using the amount of moles, we must multiply by Avagadro's number.

(3.75mol) × (6.02 × 10²³) = 2.26 × 10²⁴ atoms of Fe

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What is the oxidation number of tin (Sn) in the compound Na2SnO2? A. -2 B. 0 C. +2 D. +3

Allisa [31]

O.N. of Na = +1

O.N. of O = -2

Let, O.N. of Tin = x

1*2 + x + -2*2 = 0

2+x-4 = 0

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3 years ago

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Explanation:

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2 years ago

How many moles of ions are there in 3 moles of calcium chloride?

klemol [59]

Answer:

9 moles of ions

Explanation:

Our compound is: CaCl₂(s)

We dissociate it:

CaCl₂(aq) → Ca²⁺ (aq) + 2Cl⁻(aq)

Per 1 mol of chloride, we have 1 mol of calcium cation and 2moles of chlorides, so in total we have 3 moles of ions.

Therefore in 3 moles of chloride, we would have 9 moles of ions (3 . 3)

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3 years ago

The total variety of organisms that live in the biosphere

RUDIKE [14]

The sum total of the genetically based variety of living organisms in the biosphere is called a. species diversity. c. biodiversity.

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3 years ago

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How many grams of CaCl2 are needed to make 277.8g of a solution that is 31.5% (m/m) in water? Note that mass is not technically

Sveta_85 [38]

Answer: The mass of calcium chloride present in given amount of solution is 87.5 g

Explanation:

We are given:

Mass of solution = 277.8 grams

Also, 31.5 % (m/m) of calcium chloride in water. This means that 31.5 g of calcium chloride is present in 100 g of solution.

To calculate the mass of calcium chloride in the given amount of solution, we use unitary method:

in 100 g of solution, the mass of calcium chloride present is 31.5 g

So, 277.8 g of solution, the mass of calcium chloride present is $\frac{31.5}{100}\times 277.8=87.5g$

Hence, the mass of calcium chloride present in given amount of solution is 87.5 g

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3 years ago