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Xelga [282]
3 years ago
13

#1: The following reaction occurs in a voltaic cell: Cu2+ + Zn --> Zn2+ + Cu. Which of the following reactions occurs at the

anode?
A. Cu2+ + Zn --> Zn2+ + 2e-

B. Cu2+ + 2e- --> Cu

C. Zn --> Zn2+ + 2e-

D. Cu2+ + 2e- --> Zn2+ + Cu
Chemistry
1 answer:
Rudiy273 years ago
5 0
In a voltaic cell there are two electrodes: anode and cathode.

On the cathode, the reaction that occurs is reduction, which means that the metal gains electrons.

On the anode the reaction is oxidation, which means that the metal loses electrons.

In this voltaic cell the reaction on the anode is:

Zn --> Zn 2+  + 2e-, i.e. option C.

Answer: option C.
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Answer:

Tetrahedral molecules are normally spy hybridized.

Explanation:

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3 years ago
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Typical "hard" water contains about 2.0 x 10–3 mol of Ca2+ per liter. Calculate the maximum concentration of fluoride ion that c
malfutka [58]

Answer:

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Explanation:

Hello,

In this case, for the described situation, we infer that calcium reacts with fluoride ions to yield insoluble calcium fluoride as shown below:

Ca^{+2}(aq)+2F^-(aq)\rightleftharpoons CaF_2(s)

Which is typically an equilibrium reaction, since calcium fluoride is able to come back to the ions. In such a way, since the maximum amount is computed via stoichiometry, we can see a 1:2 mole ratio between the ions, therefore, the required maximum amount of fluoride ions in the "hard" water (assuming no other ions) turns out:

[F^-]_{max}=2.0x10^{-3}\frac{molCa^{2+}}{L}*\frac{2molF^-}{1molCa^{2+}}  \\

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

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8 0
3 years ago
How many joules of heat are required to raise the temperature of 320.0 grams of water from 24.2°C to 50.8°C? Heat capacity of wa
balu736 [363]

Answer:

35750.4 Joules

Explanation:

Using the formula as follows;

Q = m × c × ∆T

Where;

Q = amount of heat (joules)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

According to the provided information,

mass (m) = 320.0 grams

c = 4.2 J/g°C

∆T = (50.8°C - 24.2°C) = 26.6°C

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Using; Q = m × c × ∆T

Q = 320 × 4.2 × 26.6

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5 0
3 years ago
A container of oxygen with a volume of 60 L is heated from 300 K to 400 k, What is the new volume?
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Answer:

80L

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V1/T1 = V2/T2

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V2 = 80L

7 0
3 years ago
What 100 plus 124000
kodGreya [7K]
100 + 124000 = 124100
6 0
3 years ago
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