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Xelga [282]
2 years ago
13

#1: The following reaction occurs in a voltaic cell: Cu2+ + Zn --> Zn2+ + Cu. Which of the following reactions occurs at the

anode?
A. Cu2+ + Zn --> Zn2+ + 2e-

B. Cu2+ + 2e- --> Cu

C. Zn --> Zn2+ + 2e-

D. Cu2+ + 2e- --> Zn2+ + Cu
Chemistry
1 answer:
Rudiy272 years ago
5 0
In a voltaic cell there are two electrodes: anode and cathode.

On the cathode, the reaction that occurs is reduction, which means that the metal gains electrons.

On the anode the reaction is oxidation, which means that the metal loses electrons.

In this voltaic cell the reaction on the anode is:

Zn --> Zn 2+  + 2e-, i.e. option C.

Answer: option C.
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The activation energy for proline isomerization of a peptide depends on the identity of the preceding residue and obeys Arrheniu
MAVERICK [17]

Answer:

Activation energy of phenylalanine-proline peptide is 66 kJ/mol.

Explanation:

According to Arrhenius equation-     k=Ae^{\frac{-E_{a}}{RT}}    , where k is rate constant, A is pre-exponential factor, E_{a} is activation energy, R is gas constant and T is temperature in kelvin scale.

As A is identical for both peptide therefore-

                                   \frac{k_{ala-pro}}{k_{phe-pro}}=e^\frac{[E_{a}^{phe-pro}-E_{a}^{ala-pro}]}{RT}

Here \frac{k_{ala-pro}}{k_{phe-pro}}=\frac{0.05}{0.005} , T = 298 K , R = 8.314 J/(mol.K) and E_{a}^{ala-pro}=60kJ/mol

So, \frac{0.05}{0.005}=e^{\frac{[E_{a}^{phe-pro}-(60000J/mol)]}{8.314J.mol^{-1}.K^{-1}\times 298K}}

   \Rightarrow E_{a}^{phe-pro}=65705J/mol=66kJ/mol (rounded off to two significant digit)

So, activation energy of phenylalanine-proline peptide is 66 kJ/mol

7 0
2 years ago
Increasing the amount of current flowing through a wire strengthens
vagabundo [1.1K]

Answer:

It will strengthen Electromagnetism

8 0
2 years ago
How do I balance this equation?
gavmur [86]

Answer: place a 2 in front of NaNo3 on left side of equation while leaving the other blanks empty or you can place a 1 in those blanks

Explanation:

Step 1 count and write down the amount of each given element for both sides

Step 2 begin placing numbers (coefficients) to each side to balance

7 0
2 years ago
1. Review the information in the table below. Use the information to calculate rate of how many sandwiches are made in a 10-minu
PilotLPTM [1.2K]

Answer:

The answer to your question is given below.

Explanation:

Rate is simply defined as quantity per unit time. Mathematically it is represented as:

Rate = Quantity /time

Thus, we can obtain the rate as follow:

1. Quantity = 20 sandwich

Time = 10 mins

Rate =?

Rate = Quantity /time

Rate = 20/10

Rate = 2 sandwich per mins

2. Quantity = 30 sandwich

Time = 10 mins

Rate =?

Rate = Quantity /time

Rate = 30/10

Rate = 3 sandwich per mins

3. Quantity = 40 sandwich

Time = 10 mins

Rate =?

Rate = Quantity /time

Rate = 40/10

Rate = 4 sandwich per mins

4. Quantity = 50 sandwich

Time = 10 mins

Rate =?

Rate = Quantity /time

Rate = 50/10

Rate = 5 sandwich per mins

Thus, the complete table is given as follow:

Quantity >> Unit of measure >> Rate

10 >>>>>>> 10 min >>>>>>>>>> 1

20 >>>>>>> 10 min >>>>>>>>>> 2

30 >>>>>>> 10 min >>>>>>>>>> 3

40 >>>>>>> 10 min >>>>>>>>>> 4

50 >>>>>>> 10 min >>>>>>>>>> 5

4 0
2 years ago
If you are administering an insulin dose of 90.0 mg from a bottle at a concentration of 10.0 mg/mL,
Fiesta28 [93]

Answer:

9 mL.

Explanation:

Dosage of insulin is 90 mg

The concentration of insulin is 10 mg/mL

We need to find how many milliliters of the solution do you need to give the patient. It can be calculated as follows :

x=\dfrac{90\ \text{mg}}{10\dfrac{\text{mg}}{\text{mL}}}\\\\x=\dfrac{9}{1}\ \text{mL}

So, 9 mL of the solution is to be given to the patient.

4 0
2 years ago
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