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1 year ago

A 0.50-quart jar contains 2.0 pounds of honey. what is the density of the honey in g/ml?

Chemistry

1 answer:

grin007 [14]1 year ago

5 0

A 0.50-quart jar contains 2.0 pounds of honey. 1.9 g/ml is the density of the honey.

Density is a measure of how much "stuff" is in a given space. For example, a block of the heavy element lead (Pb) is denser than the softer, lighter element gold (Au). Styrofoam blocks are less dense than bricks. Defined as mass per unit volume.

The density of an object is one of the most important and easiest physical properties to measure. Density is commonly used to identify pure substances and to characterize and estimate the composition of various types of mixtures. Density is an important concept because it can determine which substances float and which sink when placed in a liquid. In general, matter floats as long as its density is less than that of the liquid.

Learn more about density here

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The water cycle imagine you are a rain drop

Soloha48 [4]

Evaporation,condensation,precipitation,sublimation,transpirtation,runoff and infiltration

7 0

3 years ago

Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0

4 years ago

A 13.1-g sample of CaCl2 is dissolved in 104 g of water, with both substances at 24.7°C. Calculate the final temperature of the

likoan [24]

Answer:

The final temperature of the solution is 44.8 °C

Explanation:

assuming no heat loss to the surroundings, all the heat of solution (due to the dissolving process) is absorbed by the same solution and therefore:

Q dis + Q sol = 0

Using tables , can be found that the heat of solution of CaCl2 at 25°C (≈24.7 °C) is q dis= -83.3 KJ/mol . And the molecular weight is

M = 1*40 g/mol + 2* 35.45 g/mol = 110.9 g/mol

Q dis = q dis * n = q dis * m/M = -83.3 KJ/mol * 13.1 g/110.9 gr/mol = -9.84 KJ

Qdis= -9.84 KJ

Also Qsol = ms * Cs * (T - Ti)

therefore

ms * Cs * (T - Ti) + Qdis = 0

T= Ti - Qdis * (ms * Cs )^-1 =24.7 °C - (-9.84 KJ/mol)/[(104 g + 13.1 g)* 4.18 J/g°C] *1000 J/KJ

T= 44.8 °C

7 0

4 years ago

What would be the molarity of a solution in which 0.56 mole of NaCl is dissolved in enough water to make 2.7 L of solution?

yan [13]

Answer:

Molarity = 0.21 M

Explanation:

Moles solute (mol) = Volume solution (L) x Molarity solution (M)

0.56 mol NaCl = 2.7 L x M

M = 0.2074074074

5 0

2 years ago

2. How many chlorine atoms are in 4 moles of chlorine?

RUDIKE [14]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers