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Cloud [144]
3 years ago
7

Identify four properties of a substance that will never change

Chemistry
2 answers:
Aleonysh [2.5K]3 years ago
7 0
Density
Colour
Conductivity
Malleability
and Luster
worty [1.4K]3 years ago
4 0

Answer:

Density, boiling point, melting point, condensation point.

Explanation:

The characteristic properties of a chemical substance are defined as the <u>fixed and unique properties</u> that are used for the identification and the classification of the given substance.

They can be physical as well as chemical properties such as <u>density, solubility, freezing point, boiling point, melting point, condensation point, and viscosity.</u>

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Find the number of moles of water that can be formed if you have 126 mol of hydrogen gas and 58 mol of oxygen gas.
Elden [556K]

Since a water molecule is H2O, you would divide 126 hydrogen molecules by 2, and you would get 63. That means you have 63 double hydrogen molecules, and 58 oxygen molecules to pair up with them. So that means you could have 58 molecules of water, with 5 double hydrogen molecules, so basically 10 extra molecules of hydrogen along with the H2O molecules. Hope I helped! :)

6 0
3 years ago
Read 2 more answers
Name the following compound:<br> CH3-CH2-CH2-CH2-CH3<br> CH3 CH3
stepan [7]

Answer:

<u><em>Pentane </em></u>

Explanation:

since we have in here CH3-CH2-CH2-CH2-CH3 5 Carbon atoms and 12 Hydrogen making it C_{5} H_{12}

6 0
3 years ago
Consider the reaction at 500 ° C 500°C . N 2 ( g ) + 3 H 2 ( g ) − ⇀ ↽ − 2 NH 3 ( g ) K c = 0.061 N2(g)+3H2(g)↽−−⇀2NH3(g)Kc=0.06
Sav [38]

Answer:

Q = 0.061 = Kc

Explanation:

Step 1: Data given

Temperature = 500 °C

Kc=0.061

1.14 mol/L  N2

5.52 mol/L H2

3.42 mol/L NH3

Step 2: Calculate Q

Q=[products]/[reactants]=[NH3]²/ [N2][H2]³

If Qc=Kc then the reaction is at equilibrium.  

If Qc<Kc then the reaction will shift right to reach equilibrium.

If Qc>Kc then the reaction will shift left to reach equilibrium.  

Q = (3.42)² / (1.14 * 5.52³)

Q = 11.6964/191.744

Q = 0.061

Q = Kc the reaction is at equilibrium.  

4 0
3 years ago
The rock in a lead ore deposit contains 89 % PbS by mass. How many kilograms of the rock must be processed to obtain 1.5 kg of P
Zolol [24]

Answer:

Approximately 1.9 kilograms of this rock.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Pb: 207.2;
  • S: 32.06.

To answer this question, start by finding the mass of Pb in each kilogram of this rock.

89% of the rock is \rm PbS. There will be 890 grams of \rm PbS in one kilogram of this rock.

Formula mass of \rm PbS:

M(\mathrm{PbS}) = 207.2 + 32.06 = 239.26\; g\cdot mol^{-1}.

How many moles of \rm PbS formula units in that 890 grams of \rm PbS?

\displaystyle n = \frac{m}{M} = \rm \frac{890}{239.26} = 3.71980\; mol.

There's one mole of \rm Pb in each mole of \rm PbS. There are thus \rm 3.71980\; mol of \rm Pb in one kilogram of this rock.

What will be the mass of that \rm 3.71980\; mol of \rm Pb?

m(\mathrm{Pb}) = n(\mathrm{Pb}) \cdot M(\mathrm{Pb}) = \rm 3.71980 \times 207.2 = 770.743\; g = 0.770743\; kg.

In other words, the \rm PbS in 1 kilogram of this rock contains \rm 0.770743\; kg of lead \rm Pb.

How many kilograms of the rock will contain enough \rm PbS to provide 1.5 kilogram of \rm Pb?

\displaystyle \frac{1.5}{0.770743} \approx \rm 1.9\; kg.

5 0
4 years ago
Which substances are broken down by chemical means
solniwko [45]

Compounds

Explanation:

Compounds are substances that can be broken down by chemical means. They are categorized as pure substances due to their definite composition.

  • Compounds are substances composed of two or more kinds of atoms or elements joined together in a definite grouping.
  • Properties of compounds differs from those of the constituent atoms.
  • Compounds are broken down by chemical means because they are products of chemical changes.
  • Several kinds of compounds exists through combinations of atoms.
  • Compounds have definite compositions

Learn more:

Compounds and bonds brainly.com/question/11064344

#learnwithBrainly

8 0
3 years ago
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