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avanturin [10]
2 years ago
6

In a combination reaction, 2.22 g of magnesium is heated with 3.75 g of nitrogen.

Chemistry
1 answer:
mariarad [96]2 years ago
8 0

Nitrogen is present in excess.

<h3>What is the no. of moles of nitrogen?</h3>

3Mg + N2 = Mg3N2

Moles of Mg = mass / molar mass = 2.22 / 24.3 = 0.0914

Moles of N2 = 3.75 / 28=0.1339

In conclusion, as we produce less amount of M g3N 2 when we assumed that M g was the limiting reagent, magnesium is the limiting reagent and nitrogen is the excess.

<h3>How can magnesium nitride be made through a direct reaction?</h3>

The elements can directly react to form magnesium nitride, as demonstrated in the equation 3 mg (s)+n2 (g)=Mg3N2 (s).

<h3>What is excess reactant?</h3>

Reactants that are not totally consumed are referred to as "excess reactants," whereas reactants that are completely consumed or reacted are referred to as "limited reactants." How much of the limiting reactants are consumed determines how much product is generated. In this section, the definition of excess reactant, examples, and calculations are discussed.

Learn more about magnesium nitride:

brainly.com/question/20980092

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How many grams of AICI: are needed to produce 150 grams of NaCl?
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HELP PLEASE I HAVE A TEST TODAY AND I DON'T UNDERSTAND ANY OF THIS...
myrzilka [38]

Answer:

About 67 grams or 67.39 grams

Explanation:

First you would have to remember a few things:

 enthalpy to melt ice is called enthalpy of fusion.  this value is 6.02kJ/mol

  of ice  

 it takes 4.18 joules to raise 1 gram of liquid water 1 degree C

 water boils at 100 degrees C and water melts above 0 degrees C

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  water's enthalpy of vaporization (steam) is 40.68 kJ/mol

  a mole of water is 18.02 grams

  we also have to assume the ice is at 0 degrees C

Step 1

Now start with your ice.  The enthalpy of fusion for ice is calculated with this formula:

q = n x ΔH    q= energy, n = moles of water, ΔH=enthalpy of fusion

Calculate how many moles of ice you have:

150g x (1 mol / 18.02 g) = 8.32 moles

Put that into the equation:

q = 8.32 mol x 6.02 = 50.09 kJ of energy to melt 150g of ice

Step 2

To raise 1 gram of water to the boiling point, it would take 4.18 joules times 100 (degrees C)  or 418 joules.

So if it takes 418 joules for just 1 gram of water, it would take 150 times that amount to raise 150g to 100 degrees C.  418 x 150 = 62,700 joules or 62.7 kilojoules.

So far you have already used 50.09 kJ to melt the ice and another 62.7 kJ to bring the water to boiling.  That's a total of 112.79 kJ.

Step 3

The final step is to see how much energy is left to vaporize the water.

Subtract the energy you used so far from what you were told you have.

265 kJ - 112.79 kJ = 152.21 kJ

Again q = mol x ΔH (vaporization)

You know you only have 152.21 kJ left so find out how many moles that will vaporize.

152.21 kJ = mol x 40.68  or   mol = 152.21 / 40.68  = 3.74 moles

This tells you that you have vaporized 3.74 moles with the energy you have left.

Convert that back to grams.

3.74 mol   x  ( 18.02 g / 1 mol ) = 67.39 grams

5 0
2 years ago
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