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Nezavi [6.7K]
3 years ago
8

What place is a landscape featured that forms when plate movement forces the crust to bend downward

Chemistry
1 answer:
Olenka [21]3 years ago
7 0
The answer is syncline
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How do you convert 34.6 kilograms to micrograms?<br> Also the Steps that got you that answer
saw5 [17]
40.28 sorry if it is wrong:) but I tried
8 0
4 years ago
How many grams are in 52grams of Ca3(PO3)2
Minchanka [31]
How many grams or atoms
4 0
3 years ago
Copper metal reacts with hot concentrated sulfuric acid solution to form aqueous copper(ii) sulfate, sulfur dioxide gas, and wat
Alex777 [14]
The unbalanced chemical equation with the corresponding phase for each substance is shown below: 

Cu₍s₎ + H₂SO₄₍aq₎ → CuSO₄₍aq₎ + SO₂₍g₎ + H₂O₍l₎

The copper metal is solid, the sulfuric acid and copper sulfate are in aqueous solution. Water is in the liquid phase while sulfur dioxide is in the gas phase. 

In order to obtain the balanced equation, we must ensure that the number of atoms present in the reactant side is equal to that in the product side. First, we list the elements involved and count their number on each side.

Reactant           Product
   1             Cu      1
   2              H       2
   1              S       2
   4              O       5

To balance the equation, we need to have 2 moles of H₂SO₄ and 2 moles of H₂O. The balanced chemical equation is then:

Cu₍s₎ + 2H₂SO₄₍aq₎ → CuSO₄₍aq₎ + SO₂₍g₎ + 2H₂O₍l₎

Reactant           Product
   1             Cu      1
   4              H       4
   2              S       2
   8              O       8
3 0
3 years ago
Assume the following is a neutral atom.
Lena [83]

Answer:

2. carbon

Explanation:

carbon should be the answer

4 0
3 years ago
Calculate the molality of a solution containing 257 g glucose (c6h12o6) dissolved in 1.62 l of water. assume a density of 1.00 g
Alex777 [14]
Molality is defined as the number of moles of solute in 1 kg of solvent.
since density and volume has been given we can calculate the mass of water
mass = density x volume
mass = 1.00 g/mL x 1620 mL = 1620 g
number of moles of glucose - 257 g / 180 g/mol = 1.43 mol
number of moles of glucose in 1620 g - 1.43 mol
therefore number of moles in 1000 g - 1.43 mol / 1.620 kg = 0.883 mol/kg
therefore molality is 0.883 mol/kg
4 0
4 years ago
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