The movement of gases through pinhole is called effusion and the effusion rate indirectly proportional to the molar mass of gas
The lighter mass gas effuses faster than the heavier one
so He(g) will escapes faster and it will move with higher average speed because it has less mass than Ne(g)
Answer:
-3.19x10³ J
Explanation:
Since the surroundings absorbed 3.19 × 10³ J (or 3190 J) of heat, the system, or the dissolution reaction, must have lost the same amount of heat. The heat for the system, then, is -3.19 × 10³ J (or -3190 J). We know this is true because of the first law of thermodynamics, "heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy".
Given what we know, we can confirm that the type of van der Waals interactions that occur between molecules of O2, SCl2, and CH4 in liquids of these substances are the presence of <u>London dispersion forces</u>.
<h3>What are London dispersion forces?</h3>
- They are a force of attraction between atoms.
- They are generated by electrostatic attraction.
- These forces are common between atoms in close proximity and occur often when compounds have a symmetrical distribution of atoms.
- They are generated by the formation of temporary dipoles.
Therefore, given the symmetry of the atoms disposition in these compounds and the temporary dipoles generated by the atoms being in close proximity, we can confirm that the van der Waals forces present in each compound are London dispersion forces.
To learn more about van deer Waals forces visit:
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Answer:
Methane -1,Ethene 2 , Ethane 2,Pentane 5,Propene 3,Hexane 6,Ethyne 2,Propane 3,Octane 8,Heptane 7 Decane 10,Butyne 4,Butane 4,Propyne 3,Butene 4
