Question

6. How many moles of Cu(NO3)2 are in 25 ml of a 0.35 M solution of Cu(NO3)2? a) How many moles of NO3- are present in 25 ml of the above solution? b) What volume of this solution should be used to get 0.050 moles of Cu(NO3)2?

Answer 1

Explanation:

Below is an attachment containing the solution.

Answer 2

Answer:

0.00875 moles Cu(NO3)2

a) 0.0175 moles NO3-

b) We should use 0.14L

Explanation:

Step 1: Data given

Volume = 25 mL = 0.025 L

Molarity of a Cu(NO3)2 solution = 0.35 M

Step 2: Calculate moles Cu(NO3)2

Moles Cu(NO3)2 = molarity * volume

Moles Cu(NO3)2 = 0.35 M * 0.025 L

Moles Cu(NO3)2 = 0.00875 moles

Step 3: Calculate moles NO3-

Cu(NO3)2 → Cu^2+ + 2NO3-

In 1 mol Cu(NO3)2 we have 2 moles NO3-

For 0.00875 moles Cu(NO3)2 we'll have 2*0.00875 = 0.0175 moles NO3-

Step 4: What volume of this solution should be used to get 0.050 moles of Cu(NO3)2?

Volume =  moles / molarity

Volume = 0.050 moles / 0.35 M

Volume = 0.14L