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SpyIntel [72]
1 year ago
11

A restaurant offers a special pizza with any 5 toppings. if the restaurant has 16 topping from which to choose, how many differe

nt special pizzas are possible?
Mathematics
1 answer:
Mariana [72]1 year ago
5 0

By permutation without repetition, there are 524160 possible different special pizzas.

The possible special pizzas can be calculated with permutation without repetition. The formula of permutation without repetition can be written as

P = n! / (n - k)!

where P is all of the possible combinations, n is the number of objects or elements, and k is how many numbers should be chosen.

From the question above, we know that :

n = 16

k = 5

By substituting the parameters, we can determine all of the possible different pizzas

P = n! / (n - k)!

P = 16! / (16 - 5)!

P = 16! / 11!

P = 16 x 15 x 14 x 13 x 12 x 11! / 11!

P = 524160

Hence, there are 524160 possible different special pizzas

Find out more on permutation without repetition at: brainly.com/question/1216161

#SPJ4

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8x + 4 - z

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Given the following :

The distance from her house to school is 2x+5 The distance from the school to the park is z If the total distance she was that day is 10x +9 how far is it from the park back to her

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Find the length of BC.<br><br><br><br>Explain how you got it, please!<br>Thanks!
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Answer:

BC = 30.73

Here,

\sf \frac{AB}{BQ}  = \frac{CD}{DQ}

so first solve for QD

\sf \hookrightarrow \frac{32}{15}  = \frac{19.2}{DQ}

\sf \hookrightarrow 32(DQ)}  =19.2(15)

\sf \hookrightarrow 32(DQ)}  =288

\sf \hookrightarrow DQ =9

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Now! <u>using Pythagoras theorem,</u>

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2 years ago
Read 2 more answers
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