draw two lewis structures for a compound with the formula c4h10 . no atom bears a charge, and all carbon atoms have complete oct
1 answer:
The number of sigma bonds = 5, and number of pi bonds = 3 in the given compound. Shown in attachment are the two Lewis structures of the compound with molecular formula C4H10. The two structures are the isomers of each other.
Butane is an alkane represented by C4H10. All the bonds in this situation are single bonds because this substance is an alkane. Two shared electrons are present in every bond.
Each carbon atom requires 8 electrons around it in order to follow the Octet Rule. The octet rule was completed by the hydrogen bonds, eliminating the need for the electron dots.
Straight-chained butane is the first structure. The y-chained isobutane is the second structure.
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This question provides us –
- Weight of
is = 47 g
- Volume, V = 375 mL
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- Molar Mass of
–
<u>Using formula</u> –
- Henceforth, Molarity of the solution is = 1.7M
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