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4 years ago

Which type of mirror produces images that are always upright and at the same distance from the mirror as the object is?

Physics

2 answers:

Nezavi [6.7K]4 years ago

8 0

<h3>Answer;</h3>

Flat mirror

<h3>Explanation;</h3>

A flat mirror or a plane mirror forms images that are always at equal distance as the object from the mirror. The images formed by a pane mirror are always virtual and the size of the image is the same as that of the object.
Plane mirrors and convex mirrors only produces virtual images. Concave mirrors are the only mirrors that are capable of forming real images and occurs only when the object is located a distance greater than a focal length of the mirror.

Alex73 [517]4 years ago

7 0

Well, that would be a plane (flat) mirror
provided that 
the mirror and the object are oriented parallel to each other

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The wheel on an upside-down bicycle moves through 18.0 rad in 5.39 s. What is the wheel’s angular acceleration if its initial an

Elden [556K]

Explanation:

Formula to calculate angular acceleration is as follows.

$\Delta (\theta) = \frac{1}{2} \alpha \Delta t^{2} + \omega_{1} \Delta t$

or, $\alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}$

Putting the given values into the above formula as follows.

$\alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}$

= $\frac{2(18.0 rad - 2.5 rad/s \times 5.30 s)}{(5.39)^{2}}$

= 0.326 $rad/s^{2}$

Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326 $rad/s^{2}$ .

5 0

3 years ago

For the chemical reaction below, determine the amount of hi produced when 3.35 g of hydrogen is reacted with 50.75 g of iodine t

ra1l [238]

Molar mass of H₂ = 1.008 × 2 g/mol = 2.016 g/mol 
Molar mass of I₂ = 126.9 × 2 g/mol = 253.8 g/mol 
Molar mass of HI = (1.008 + 126.9) g/mol = 127.9 g/mol

H₂(g) + I₂(g) → 2HI 
Mole ratio H₂ : I₂ : HI = 1 : 1 : 2 

Then the initial number of moles of H₂ = (3.35 g) / (2.016 g/mol) = 1.662 mol 
Initial number of moles of I₂ = (50.75 g) / (253.8 g/mol) = 0.2000 mol < 1.662 mol 
Hence, I₂ is the limiting reactant (limiting reagent). 

Number of moles of I₂ reacted = 0.2000 mol 
Number of moles of HI reacted = (0.2000 mol) × 2 = 0.4000 mol
Mass of HI reacted = (127.9 g/mol) × (0.4000 mol) = 51.16 g

8 0

4 years ago

What is the magnitude acceleration of a body in a projectile motion at the highest point

MrRa [10]

Answer:

Zero

Explanation:

At a projectile's highest point, its velocity is zero. At a projectile's highest point, its acceleration is zero

6 0

3 years ago

In unit-vector notation, what is the net torque about the origin on a flea located at coordinates (-2.0, 4.0 m, -1.0 m) when for

kifflom [539]

Answer:

Torque, $\tau=-21i-8j+10k$

Explanation:

Given that,

Coordinates, $r=(-2i+4j-k)\ m$

Force acting on the flea, $F=(0i-5j-4k)\ N$

Let $\tau$ is the net torque about the origin on a flea. It is given by the following formula :

$\tau=r\times F$

$\tau=(-2i+4j-k)\times (0i-5j-4k)$

$\tau=\begin{pmatrix}-21&-8&10\end{pmatrix}$

$\tau=-21i-8j+10k$

So, the net torque about the origin on a flea is $-21i-8j+10k$ . Hence, this is the required solution.

6 0

3 years ago

An object was dropped from the plane with 1000 km above the ground with a mass of 300 kg. Find the acceleration of the object ea

Oxana [17]

Answer:

$9.8m/s^2$

Explanation:

The acceleration due to gravity on earth is $9.8m/s^2$ regardless of the mass of the object. This means, in the absence of air resistance, both a 3000 kg object and a 300 kg will accelerate at the same rate of $9.8m/s^2$ towards earth.

The reason the acceleration due to gravity is the same for all masses is that by grace of nature, the inertial mass $m$ of the object from $F= ma$ equals the gravitational mass $m$ from $F =G \dfrac{mM}{R^2}$ , resulting

$ma=G\dfrac{mM}{R^2}$

$\boxed{a=G\dfrac{M}{R^2}}$

which is the acceleration that only depends on the mass of earth and its radius, and not on the mass of the object.

8 0

4 years ago