All categories

3 years ago

Which type of mirror produces images that are always upright and at the same distance from the mirror as the object is?

Physics

2 answers:

Nezavi [6.7K]3 years ago

8 0

<h3><u>Answer;</u></h3>

Flat mirror

<h3><u>Explanation;</u></h3>

<em><u>A flat mirror or a plane mirror forms images that are always at equal distance as the object from the mirror. The images formed by a pane mirror are always virtual and the size of the image is the same as that of the object.</u></em>
<em><u>Plane mirrors and convex mirrors only produces virtual images. Concave mirrors are the only mirrors that are capable of forming real images and occurs only when the object is located a distance greater than a focal length of the mirror.</u></em>

Alex73 [517]3 years ago

7 0

Well, that would be a plane (flat) mirror
<span>provided that </span>
<span>the mirror and the object are oriented parallel to each other</span>

You might be interested in

1.55 J of work was done on the object that moved 5 meters. How much force was applied to the

Firdavs [7]

Answer:

Work=force x displacement

Force =work/ displacement

F=1.55/5

F=0.31N

Explanation:

3 0

2 years ago

When an object is lifted 12 meters off the ground, it gains a certain amount of potential energy. If the same object is lifted 2

alexandr402 [8]

I think the answer is twice as much

8 0

2 years ago

Work is done on an object when an applied force causes the object to move in the same direction as the force.

Lelu [443]

Answer:yes

Explanation:

Work is done on an object when an applied force causes the object to move in the same direction as the force

3 0

3 years ago

The electric field 2.5 mm from a uniform sheet of charge is σ=800, NC. How much charge is contained in a 5.0x5.0 cm section of t

slamgirl [31]

Answer:

The charge is $2.75\times10^{-13}\ C$

Explanation:

Given that,

Distance = 2.5 mm

Electric field = 800 NC

Length $L=5.0\times5.0\times10^{-4}\ m$

We need to calculate the linear charge density

Using formula of linear charge density

$E=\dfrac{2k\lambda}{r}$

$\lambda=\dfrac{Er}{2k}$

Put the value into the formula

$\lambda=\dfrac{800\times2.5\times10^{-3}}{2\times9\times10^{9}}$

$\lambda=1.1\times10^{-10}\ C/m$

We need to calculate the charge

Using formula of charge

$Q=\lambda\timesL$

Put the value into the formula

$Q=1.1\times10^{-10}\times(5.0\times5.0\times10^{-4})$

$Q=2.75\times10^{-13}\ C$

Hence, The charge is $2.75\times10^{-13}\ C$

5 0

3 years ago

Which statement best summarizes the central idea of “Applications of Newton’s Laws”?

Shkiper50 [21]

Newton's three forces, normal, tension and friction, are present in a surprising number of physical situations

Newton's Laws, that describe the relationship between an obejct and the forces acting upon it, apply in almost every physical situation, from quantum mechanics to electricity.

The correct answer is:

Newton’s laws can explain the forces that occur between objects every day

3 0

3 years ago

Read 2 more answers