Acceleration = V/t
First set velocity to m/s
V = 72.42 m/s
Now we divide velocity by time
A = 72.42/39.5
A = 1.83 m/s^2
They give us the cable tension t = 1500 newton. We assume that the mass of the cable is negligible compared to that of the tower.
We have a force t of 1500 Newton. This force has a vertical component on the y axis and a horizontal component on the x axis.
Of these two components of force, we are especially interested in calculating is the magnitude of the vertical component.
If the angle that it forms with the ground is 50 °, then the vertical component of the force is:
Fy = 1500sin (50)
Fy = 1149 N. <1200 N
The wire will not be loose
Answer:
Work done is 882000joule.
power is 29400watt.
Explanation:
given,
Mass(m)=500kg
Acceleration due to gravity(g)=9.8m/s²
Height(h)=6m
Time taken(t)=30s
Workdone=?
Power=?
now,
workdone=force*displaxement
= m*g*h
=500*9.8*6
=8,82,000joule
so, the work done by the man is 8,82,000joule.
then,
power=workdone/time taken
=8,82,000/30
=29,400watt
so, the required power to lift a load is 29,400watt.
