Answer:
16.9000000000000001 J
Explanation:
From the given information:
Let the initial kinetic energy from point A be = 1.9000000000000001 J
and the final kinetic energy from point B be = ???
The charge particle Q = 6 mC = 6 × 10⁻³ C
The change in the electric potential from point B to A;
i.e. V_B - V_A = -2.5 × 10³ V
According to the work-energy theorem:
-Q × ΔV = ΔK
Answer:
a) The x and y components of the momentum are and
, respectively.
b) The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.
Explanation:
a) The vectorial equation of momentum is represented by the following expression:
(1)
Where:
- Vector momentum, measured in kilogram-meters per second.
- Mass of the particle, measured in kilograms.
- Vector velocity, measured in meters per second.
If we know that and
, then the momentum is:
The x and y components of the momentum are and
, respectively.
b) The magnitude and direction of momentum are represented by the following expressions:
(2)
(3)
Where:
- Magnitude of momentum, measured in kilogram-meters per second.
- Direction of momentum, measured in sexagesimal degrees.
If we know that and
, then the magnitude and direction of momentum are, respectively:
The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.