Speed = 500m/5min = 100 m/min. Direction = west. Velocity = 100 m/min west.
The magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
<h3>
Magnitude of required force to stop the weight</h3>
The magnitude of the force required to stop the weight in 0.333 seconds is calculated by applying Newton's second law of motion as shown below;
F = ma
F = m(v/t)
F = (mv)/t
F = (5 x 4.5)/0.333
F = 67.6 N
Thus, the magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
Learn more about force here: brainly.com/question/12970081
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If you have a string that is fixed on both ends the amplitude of the oscillation must be zero at the beginning and the end of the string. Take a look at the pictures I have attached. It is clear that our fundamental harmonic will have the wavelength of:
All the higher harmonics are just multiples of the fundamental:
Three longest wavelengths are:
Answer:
torque = 3.897 N-m
Explanation:
given data
force = 300 N
angle = 60 degree
distance = 15 cm
to find out
torque
solution
we will apply here torque formula that is given below
torque = force × sinθ × distance ...................1
put here all these value in equation 1
we get torque
torque = force × sinθ × distance
torque = 300 × sin60 × 1.5 ×
torque = 300 × 0.8660 × 1.5 ×
torque = 259.80 × 1.5 ×
torque = 389.711 ×
torque = 3.897 N-m
Answer:
A) A negative charge of value Q is induced on sphere B
B) there is an attraction between sphere
C) The charge of sphere A is distributed between the two spheres,
Explanation:
This is an electrostatic problem, in general charges of the same sign attract and repel each other.
with this principle let's analyze the different situations
A) The sphere A that is insulating has a charge on its surface and zero charge is its interior
The conducting sphere B has zero charge, but the sphere A creates an attraction in the electrons, therefore a negative charge of the same value as the charge of the sphere A is induced in the part closest and in the part farther away than one that a positive charge.
A negative charge of value Q is induced on sphere B
B) In this case there is an attraction between sphere A with positive charge and sphere B with negative induced charge
C) When the two spheres come into contact, the charge of sphere A is distributed between the two spheres, therefore each one has a positive charge of value half of the initial charge, as now we have net positive charges in the two spheres charges of the same sign repel each other so the spheres separate
