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bonufazy [111]
2 years ago
5

Which types of galaxies have a clearly defined disk component? irregulars only spirals only ellipticals only both spirals and el

lipticals
Physics
1 answer:
nasty-shy [4]2 years ago
4 0

Answer:

Spiral galaxies, barred spiral galaxies, and lenticular galaxies have a clearly defined disk component Spiral Galaxies consist of a central bulge and protruding arms. Sometimes, they have two arms that connect in a bar that crosses the center, and this is called a barred spiral galaxy.

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PHYSICS. <br> ……………………………………………….
belka [17]

Answer:

Work, W = F * d, and

Work = change in kinetic energy, so W=deltaKE.

Hence,

deltaKE=F * d

(1/2)*m*v^2 =F * d

d=[(1/2)*m*v^2]/F

d=[(1/2)*0.6*20^2]/5

d=24 m.

Explanation:

Work = change in kinetic energy, so W=deltaKE.

5 0
2 years ago
What do you mean by pressure of a liquid? Write its Sl unit.​
Maurinko [17]

Answer:

Explanation:

The pressure of a liquid is the rate of the force applied by the liquid on a surface per unit area of the surface.

i.e P = \frac{F}{A}

where P is the pressure, F is the force and A is the area.

The depth of the liquid determines its pressure at a definite lower point. As the pressure of a liquid at the bottom of a its container is greater than the pressure at the top of the liquid.

Thus,

P = σhg

where P is the pressure, σ is the density of the liquid, h is the height and g is the force of gravity.

It is measured in Pascals or Nm^{-2}.

The pressure of liquid has a lot of applications, viz: siphon, force pump, lift pump etc.

5 0
3 years ago
How long does a car (1000 kg) have a speed of 30 m/s from a rest if the engine power is 10kw
Lemur [1.5K]

Answer: 90.1 s

Explanation:

Use equation for power:

P=F*V

Use eqation for force:

F=ma

F---force

V---velocity

Vr=om/s

V=30m/s

m=1000kg

P=10000W

---------------------------

P=FV

F=P/V

F=10000W/30m/s

F=333.33N

Use equation for force to find accelartaion.

F=ma

a=F/m

a=333.33N/1000kg

a=0.333 m/s²

Use equation for accelaration to find out time:

a=(V-Vs)/t

t=(V-Vs)/a

t=(30m/s)/(0.333m/s²)

t=90.09 s≈90.1 s

------------------------

5 0
3 years ago
What is energy?<br> the ability to do work<br> chemical change <br> force <br> force x distance
nika2105 [10]
From my notes it’s the ability to do work
3 0
3 years ago
Given the initial wavefunction Ψ (x, 0) = Axexp (-k x) withx&gt; 0 andk&gt; 0, and Ψ (x, 0) = 0 forx &lt;0, what value must A ta
madam [21]

Answer with explanation:

The Normalization Principle states that

\int_{-\infty }^{+\infty }f(x)dx=1

Given

f(x)=xe^{-kx}(x>0\\\\0(x

Thus solving the integral we get

\int_{0 }^{+\infty }A\cdot xe^{-kx}dx=1\\\\A\int_{0 }^{+\infty }\cdot xe^{-kx}dx=1

The integral shall be solved using chain rule initially and finally we shall apply the limits as shown below

I=\int xe^{-kx}dx\\\\x\int e^{-kx}dx-\int \frac{d(x)}{dx}\int e^{-kx}dx\\\\-\frac{xe^{-kx}}{k}-\int 1\cdot \frac{-e^{-kx}}{k}\\\\\therefore I=\frac{e^{-kx}}{k}-\frac{xe^{-kx}}{k}

Applying the limits and solving for A we get

I=\frac{1}{k}[\frac{1}{e^{kx}}-\frac{x}{e^{kx}}]_{0}^{+\infty }\\\\I=-\frac{1}{k}\\\\\therefore A=-k

3 0
3 years ago
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