-0 m/s
- average velocity=displacement/time
- the runners displacement is zero so her average velocity must be zero
Answer:
Explanation:
The expression for the trigonometric function is :
L(t) = A (cos (B(t - C)))+ D ----- equation (1)
where ;
A = 0.125
D = 
D = 0.125
Period of the lunar cycle = 29.53
Then;
Also; we known that December 25 is 7 days before January 1.
Then L(-7) = 0.025
Plugging all the values into trigonometric function ; we have:
Answer:
a) 2.94 N
b) 4.90 N
Explanation:
Let us assume that the weight of the ball is 0.98 N
Solution:
a) An object’s gravitational potential energy depends on two factors which are height and its weight (or mass). The equation for gravitational potential energy (PE) is given as:
Potential energy = weight (w) * height (h)
PE = wh
Potential energy at 2 m shelf = weight * height = 0.98 N * 2 m = 1.96 N
Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N
The work needed to lift the ball from the 2-m shelf to the 5-m shelf = Potential energy at 5 m shelf - Potential energy at 2 m shelf
The work needed to lift the ball from the 2-m shelf to the 5-m shelf = 4.90 N - 1.96 N = 2.94 N
b) Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N
Answer:
Vertically
Explanation:
Pressure changes faster as we move vertically because as we go to the height from the surface of the earth. The density of air becomes lesser in comparison with the surface of the earth. So, as we move vertically pressure moves faster than in comparison with the vertical movement.
The best example that describes the above statement is the hill station.
Answer:
The number of O₂ molecules that are left in the cylinder is 1.70x10²⁴.
Explanation:
The number of oxygen molecules can be found using the Ideal Gas law:
Where:
P: is the pressure = 100 psi
V: is the volume = 10 L
n: is the number of moles =?
T: is the temperature = 20 °C = 293 K
R: is the gas constant = 0.082 L*atm/(K*mol)
Hence, the number of moles is:
Now, the number of molecules can be found with Avogadro's number:
Therefore, the number of O₂ molecules that are left in the cylinder is 1.70x10²⁴.
I hope it helps you!
