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2 years ago

5

How is the blance between oxygen and carbon dioxide maintained the atmosphere ?

1 answer:

GarryVolchara [31]2 years ago

7 0

The balance of oxygen and carbondioxide is maintained in the atmosphere by the oxygen released by plants during photosynthesis and carbondioxide released by human,animals etc. The balance of oxygen and carbondioxide is made due to respreration and photosinthesis.

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You are a support technician working in a data closet in a remote office. You suspect that a connectivity problem is related to

Nostrana [21]

Answer:

crimping tool

Explanation:

This is a tool employed in affixing a connector to the end of a network cable.

5 0

3 years ago

Which of these statements best proves that electromagnetic forces are weaker than strong nuclear forces? Neutrons do not repel o

MAVERICK [17]

Protons do not move out of the nucleus of atoms although they repel each other.

Remember that protons are particles with positive charge and they held together in the nucleus of the atom which is a tiny tiny region. As you know, like charges repel each other, which means that the protons exert a repulsion force.

8 0

2 years ago

A 20 cm-radius ball is uniformly charged to 71 nC.

artcher [175]

Answer:

Part a)

$\rho = 2.12\mu C/m^3$

Part b)

$q_1 = 1.11 nC$

$q_2 = 8.88 nC$

$q_3 = 71 nC$

Part c)

$E_1 = 3996 N/C$

$E_2 = 7992 N/C$

$E_3 = 15975 N/C$

Explanation:

Part a)

As we know that charge density is the ratio of total charge and total volume

So here the volume of the charge ball is given as

$V = \frac{4}{3}\pi R^3$

$V = \frac{4}{3}\pi(0.20)^3$

$V = 0.0335 m^3$

now the charge density of the ball is given as

$\rho = \frac{71 nC}{0.0335} = 2.12\mu C/m^3$

Part b)

Now the charge enclosed by the surface is given as

$q = \rho V$

at radius of 5 cm

$q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.05)^3$

$q = 1.11 nC$

at radius of 10 cm

$q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.10)^3$

$q = 8.88 nC$

at radius of 20 cm

$q = 71 nC$

Part c)

As we know that electric field is given as

$E = \frac{kq}{r^2}$

so we have electric field at r = 5 cm

$E_1 = \frac{(9\times 10^9)(1.11 nC)}{0.05^2}$

$E_1 = 3996 N/C$

electric field at r = 10 cm

$E_2 = \frac{(9\times 10^9)(8.88 nC)}{0.10^2}$

$E_2 = 7992 N/C$

electric field at r = 20 cm

$E_3 = \frac{(9\times 10^9)(71 nC)}{0.20^2}$

$E_3 = 15975 N/C$

3 0

2 years ago

If a car travels 60 mph for a distance of 180 miles, how much time<br> did it take?

jolli1 [7]

Answer:

3 hours

Explanation:

180 divided by 60 (mph means miles per hours by the way)

6 0

3 years ago

Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the pipi

Bas_tet [7]

Answer: The temperature of the water falls by 3.3°C

Explanation:

The heat change is related to the change in temperature by the equation

dH = m Cp dT

In this example, -2665 J = 193 g x 4.184 J/g°C x dT

so dT = -3.3 °C

3 0

3 years ago