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steposvetlana [31]
3 years ago
10

Foods rich in simple carbohydrates or starch but low in fat or fiber tend to

Chemistry
2 answers:
Alex Ar [27]3 years ago
7 0

Answer is: A. be digested and absorbed quickly.

Starch (carbohydrate) is a polymeric carbohydrate consisting of a large number of glucose units bonded by glycosidic bond.

Starch is a white, tasteless and odorless powder that is insoluble in cold water or alcohol.  

Food rich in carbohydrates has high energy content, because human body can digest it very fast.

Some fruits have a lot of cellulose (also carbohydrate) and fiber, so human body cannot digest it or digest it very slowly.

GREYUIT [131]3 years ago
5 0
A because if it was high in fiber it would go slowly that's why people eat allot of fiber a day before a race or workout
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Within the main group of elements, what do elements in a family have in common?
statuscvo [17]
They have same chemical properties
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3 years ago
How many grams of NaCI per kilogram of water are present in a 2.7 molal aqueous solution​
navik [9.2K]

Answer:

157.79 g

Explanation:

The definition of molality is:

  • molality = moles of solute / kilogram of solvent

This means that in a 2.7 molal solution, there are 2.7 moles of NaCl per kilogram of water.

So now w<u>e convert those 2.7 moles of NaCl to grams</u>, using its <em>molar mass</em>:

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3 years ago
Now that we have put a coefficient of 3 in front of caso4, what coefficient should go in front of cacl2 to balance calcium (ca)?
Ronch [10]
3 to balance the calciums on both sides of the equation, but only if that balances the Cl on both sides of the equation to because you now have 6 Cl and 3Ca 
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3 years ago
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A 0.595 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M ( s ) + H 2 SO 4 ( aq ) ⟶ MSO 4
zalisa [80]

Answer:

molar mass M(s) = 65.326 g/mol

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∴ PvH2O(25°C) = 0.03167 bar

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⇒ PH2(g) = 1.0079 bar - 0.03167 bar = 0.97623 bar = 0.9635 atm

∴ nH2(g) = PV/RT

⇒ nH2(g) = ((0.9635 atm)(0.231 L))/((0.082 atmL/Kmol)(298 K))

⇒ nH2(g) = 9.1082 E-3 mol

⇒ n M(s) = ( 9.1082 E-3 mol H2(g) )(mol M(s)/mol H2(g))

⇒ n M(s) = 9.1082 E-3 mol

∴ molar mass M(s) [=] g/mol

⇒ molar mass M(s) =   (0.595 g) / (9.1082 E-3 mol)

⇒ molar mass M(s) = 65.326 g/mol

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