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Masteriza [31]
3 years ago
15

The reaction between between common salt and concentrated tetraoxosulphate(vi) acid will liberate

Chemistry
2 answers:
Vedmedyk [2.9K]3 years ago
5 0

most prolly option D

Explanation:

NaCl + H2SO4 -> Na2SO4 + HCl[g]

sergij07 [2.7K]3 years ago
5 0
The answer would be d
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The equation 2C3H7OH + 9O2 yield 6 CO2 + 8H2O is an example of what type of reaction
Furkat [3]
Combustion reaction
3 0
3 years ago
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Find the number of cations present in 7g of sodium prosphate Na=23 g/mol O=16g/mol P=31g/mol​
Snowcat [4.5K]

Answer:    This contains magnesium, Mg2+, and hydroxide, OH–

, ions. Each magnesium ion is +2 and

each hydroxide ion is -1: two -1 ions are needed for one +2 ion, and the formula for magnesium

hydroxide is Mg(OH)2. The (OH)2 indicates there are two OH–

ions. In a formula unit of

Mg(OH)2, there are one magnesium ion and two hydroxide ions; or one magnesium, two

oxygen, and two hydrogen atoms. The subscript multiplies everything in ( )

hope that helped!!

3 0
3 years ago
what is the empirical formula of vanadium 1 oxide given that 20.38 grams of vandium combines with oxygen to form 23.58 grams of
Alex

Answer:

The empirical formula is V₂O

Empirical formula of a compound is the formula that shows the simplest whole number ratio of the atoms of elements in a given compound. Empirical formula is normally calculated when the mass of each element in a compound is known or the percentage composition by mass of each element in a compound is known.

Step by Step Explanation:

Step 1: Percentage composition of each element

Percentage composition=(mass of an element/ mass of the compound)100%

Mass of Vanadium = 20.38 g

Mass of the compound = 23.58 g

% composition of Vanadium = (20.38 g/23.58 g) 100%

                                                 = 86.43 %

Mass of Oxygen = 23.58 g -20.38 g

                           = 3.2 g

% composition of oxygen = (3.2/g/23.58 g) 100%

                                          =  13.57%

Step 2: Find the number of atoms of each element in the compound

Number of atoms  = percentage composition/ atomic mass

Atomic mass of Vanadium = 50.94 g/mol

Number of atoms of V = 86.43 /50.94

                                  = 1.6967

Atomic mass of oxygen = 16 g/mol

Number of atoms of O = 13.57/16

                                      = 0.8481

Step 3:  Find the simplest ratio of atoms

Vanadium : Oxygen

            1.6967 : 0.8481

= 1.6967/0.8481 : 0.8481/0.8481

= 2: 1

Whole number ratio = 2 : 1

Therefore; the empirical formula is V₂O

8 0
3 years ago
Read 2 more answers
Sodium peroxide (Na2O2) is often used in self-contained breathing devices, such as those used in fire emergencies, because it re
Anastaziya [24]

Answer:

725.15 L

Explanation:

The balanced chemical equation for the reaction between Na₂O₂ and CO₂ is the following:

Na₂O₂ + CO₂ → Na₂CO₃ + 1/2 O₂

From the stoichiometry of the reaction, 1 mol of Na₂O₂ reacts with 1 mol CO₂. So, the stoichiometric ratio is 1 mol Na₂O₂/1 CO₂.

Now, we convert the mass of reactants to moles by using the molecular weight (Mw) of each compound:

Mw (Na₂O₂) = (23 g/mol x 2) + (16 g/mol x 2) = 78 g/mol

moles Na₂O₂ = 96.7 g/(78 g/mol) = 1.24 mol Na₂O₂

Mw (CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol

moles CO₂ = 0.0755 g/(44 g/mol) = 1.71 x 10⁻³ mol CO₂

Now, we calculate the number of moles of CO₂ we need to completely react with the mass of Na₂O₂ we have:

1.24 mol Na₂O₂ x 1 mol CO₂/1 mol Na₂O₂ = 1.24 mol CO₂

In 1 L of respired air we have 1.71 x 10⁻³ mol CO₂ (0.0755 g), so we need the following number of liters to have 1.24 mol of CO₂:

1.24 mol CO₂ x 1 L/1.71 x 10⁻³ mol CO₂ = 725.15 L

4 0
3 years ago
A patient needs 0.024 g of a sulfa drug. There are 12-mg tablets in stock. How many tablets should be given?
emmainna [20.7K]
I would personally convert the 12 mg to g so I could see what I was working with. So 12 mg to grams is 0.012 g...

so 1 tablet is 0.012g. the patient needs 0.024 g. 

so 0.024g/0.012g = 2 tablets or 0.012g X 2 is 0.024 g

hope this helps :)
7 0
3 years ago
Read 2 more answers
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