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Alinara [238K]
1 year ago
15

Citric acid (right) is concentrated in citrus fruits and plays a central metabolic role in nearly every animal and plant cell.

Chemistry
1 answer:
arlik [135]1 year ago
8 0

<u>0.549 mol</u> of citric acid are in 1.50 qt of lemon juice (d = 1.09 g/mL) that is 6.82% citric acid.

<h3>What is citric acid?</h3>

Citric acid is an organic compound with a chemical formula ofHOC(CO_2H)(CH_2CO_2H)_2 . It is a weak organic acid that is colourless. Citrus fruits naturally produce it. It is a biochemical intermediary in the citric acid cycle, which is a process that all aerobic organisms go through during metabolism.

Every year, more than two million tonnes of citric acid are produced. It is frequently employed as a chelating agent, an acidifier, and a flavouring

Citrates, which include salts, esters, and the polyatomic anion present in solution, are derivatives of citric acid. Trisodium citrate is an example of the former; triethyl citrate is an example of an ester.

Learn more about Citric acid

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Answer:

The specific heat of the metal is 2.09899 J/g℃.

Explanation:

Given,

For Metal sample,

mass = 13 grams

T = 73°C

For Water sample,

mass = 60 grams

T = 22°C.

When the metal sample and water sample are mixed,

The addition of metal increases the temperature of the water, as the metal is at higher temperature, and the  addition of water decreases the temperature of metal. Therefore, heat lost by metal is equal to the heat gained by water.

Since, heat lost by metal is equal to the heat gained by water,

Qlost = Qgain

However,

Q = (mass) (ΔT) (Cp)

(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

After mixing both samples, their temperature changes to 27°C.

It implies that , water sample temperature changed from  22°C to 27°C and metal sample temperature changed from 73°C to 27°C.

Since, Specific heat of water = 4.184 J/g°C

Let Cp be the specific heat of the metal.

Substituting values,

(13)(73°C - 27°C)(Cp) = (60)(27°C - 22℃)(4.184)

By solving, we get Cp =

Therefore, specific heat of the metal sample is 2.09899 J/g℃.

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