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dem82 [27]
2 years ago
12

28.0 g of N2 gas was found to occupy a volume of 8.44 L at a

Chemistry
2 answers:
Pavel [41]2 years ago
5 0

Answer:

<em>Therefore, the temperature of the gas is 84.9 ℃. 28.0 g of N2 gas was found to occupy a volume of 8.44 L at a pressure of 320 kPa.</em>

Explanation:

<em>Therefore, the temperature of the gas is 84.9 ℃. 28.0 g of N2 gas was found to occupy a volume of 8.44 L at a pressure of 320 kPa.</em>

34kurt2 years ago
3 0

Are there options for this question? ...........

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The literature value for the Ksp of Ca(OH)2 at 25 °C is 4.68E−6. Imagine you ran the experiment and got a calculated value for K
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D. The Ca[OH]2 solution may have been unsaturated

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The solubility product constant Ksp of any given chemical compound is a term used to describe the equilibrium between a solid and the ions it contains solution. The value of the Ksp indicates the extent to which any compound can dissociate into ions in water. A higher the Ksp, implies more greater solubility of the compound in water.

If the Ksp is more than the value in literature, this false value must have arisen from the fact that the solution was unsaturated hence it appears to be more soluble than it should normally be when saturated.

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4 0
3 years ago
A 0.533 g sample of a carbonate salt is added to a flask. The only thing you know is that per formula unit, there is only one ca
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Answer:

\mathbf{CrCO_3}

Explanation:

The total mole of H_2SO_4 added = 15 × 1 × 10⁻³

= 15 × 10⁻³ mole

= 15 mmoles

the number of moles of NaOH added in order to neutralize the excess acid = 0.5905 ×  29.393 = 17.36 mmoles

the equation for the reaction is:

2NaOH + H_2SO_4 --------> Na_2SO_4 +2H_2O

i.e

2 moles of NaOH react with H_2SO_4

1 moles of  NaOH will react with 1/2  H_2SO_4

17.36 mmoles of NaOH = 1/2 × 17.36 mmoles of H_2SO_4

                                       = 8.68 mmoles

Number of moles of H_2SO_4 that react with MCO₃ = Total moles of H_2SO_4 added - moles of H_2SO_4 reacted with NaOH

= (15 - 8.68) mmoles

= 6.32 mmoles

H_2SO_4 + MCO_3  ------>   M_2SO_4   +    H_2O   +   CO_2

1 mole of H_2SO_4 react with 1 mole of MCO_3

6.32 mmoles of H_2SO_4 = 6.32 mmoles of MCO_3

number of moles of MCO_3 = 6.32 10⁻³ moles

mass of  MCO_3 (carbonate salt) = 0.533 g

molar mass of MCO_3  = (M+60)g/mol

We all know that ;

number of moles = mass/molar mass

Then:

6.32 10⁻³ = 0.533 / (M+60)

(M+60) = 0.533/ 6.32 10⁻³

M + 60 = 84.34

M = 84.34 - 60

M = 24.34

Thus the element with the atomic mass of 24.34 is Chromium

The chemical formula for the compound is :  \mathbf{CrCO_3}

6 0
3 years ago
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