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motikmotik
3 years ago
8

Which statement would indicate the presence of an acid?

Chemistry
2 answers:
BARSIC [14]3 years ago
8 0
Hey, it would not chnage the color and it wouldn’t react with metals so it’s between those two options. Sorry, I don’t want to say something and it’s my wrong. That’s my best guest .
kvv77 [185]3 years ago
3 0

Answer:

hey the answer is that it reacts with active metals to form a gas.

Explanation:

sorry i know this is late

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What was the gas that form in this chemical reaction
Cerrena [4.2K]
What chemical reaction??? Very vague
6 0
3 years ago
Find the molarity of 131 g Ba(NO3)2 dissolved in 750.0 water
storchak [24]

Answer:

6.68 x 10^-4

Explanation:

131g ÷ 261.337g/mol = 0.5012685 moles

0.5012685 moles ÷ 750.0 liters =

0.5012685÷ 750.0=0.000668358

6.68 x 10^-4

8 0
2 years ago
Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the freezing of water, and ex
Dafna11 [192]

Answer:

Explanation:

The total energy or intrinsic energy of a system is called the enthalpy. In thermochemistry, we have two types of enthalpy changes which are:

  • Exothermic changes
  • Endothermic changes

For the freezing of water, the enthalpy change is an exothermic one. Exothermic changes are designated as negative. In this chemical change, heat is liberated to the surroundings and this leaves the environment at a much higher temperature. In freezing, the enviroment gains more heat as the material begins to cool to lower temperature.

Entropy is the degree of randomness or disorderliness of a system. When a phase change occurs from liquid to solid, freezing takes place. Such a change increases the orderliness of a system and entropy diminishes. Here, entropy is negative.

The free energy is a measure of the energy a system that does useful work. Free energy depends on enthalpy, entropy and temperature of a system. For phase changes such as freezing of water, the value of free energy change is 0.

For this process, an increases in temperature makes it non-spontaneous. Increasing temperature would alter the course of the reaction and makes it exothermic. For entropy, increasing temperature would increase entropy and therefore, the reaction would not be feasible.

Temperature would mostly affect the free energy. An increase in temperature would increase the value of entropy change and the reaction would not be spontaneous. With falling temperature value, the reaction becomes more spontaneous and favored.

8 0
3 years ago
What is the kb of the base po−34 given that a 0. 48m solution of the base has a ph of 12. 70? the equation described by the kb v
podryga [215]

The equation described by the kb value is 5.21 x 10^-^3.

The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.

Assuming  PO₄³⁻ (the phosphate anion).

PO₄³- + H₂O ==> HPO₄²⁻ + OH⁻

Kb = [HPO₄²⁻][OH⁻] / [PO₄³⁻]

We can find the [OH⁻] from the pH of 12.70.

pH + pOH = 14

14.0 - 12.7 = 1.3 = pOH

[OH] = 1x10^-^1^.^3

[OH-] = 5.0x10^-^2 M

[HPO₄²⁻] = 5.0x10^-^2 M

Kb = (5.0x10^-^2)2 / 0.48

     = 2.5x10^-^3 / 0.48

Kb = 5.21 x 10^-^3

Learn more about pH here:

brainly.com/question/8758541

#SPJ4

3 0
1 year ago
Help!!!!!!!!!!!!!!!!!!
skad [1K]

The density of the sample : 0.827 g/L

<h3>Further explanation</h3>

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm , N/m²

V = volume, liter  

n = number of moles  

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m2, v= m³)

T = temperature, Kelvin  

n= 1 mol

MW Neon = 20,1797 g/mol

mass of Neon :

\tt mass=mol\times MW\\\\mass=1\times 20,1797 =20.1797~g

The density of the sample :

\tt \rho=\dfrac{m}{V}\\\\\rho=\dfrac{20,1797}{24.4}=0.827~g/L

or We can use the ideal gas formula ta find density :

\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{1\times 20.1797}{0.082\times 298}\\\\\rho=0.826~g/L

8 0
3 years ago
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