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3 years ago

Calculate the mass of calcium chloride that contains 3.20 x 1024 atoms of chlorine.

Chemistry

1 answer:

frez [133]3 years ago

7 0

Answer:

294.87 gm CaCl_2

Explanation:

The computation of the mass of calcium chloride is shown below:

But before that following calculations need to be done

Number of moles of chlorine atom is

= 3.20 × 10^24 ÷ 6.022 × 10^23

= 5.314 moles

As we know that

1 mole CaCl_2 have the 2 moles of chlorine atoms

Now 5.341 mole chloride atoms would be

= 1 ÷ 2 × 5.314

= 2.657 moles

Now

Mass of CaCl_2 = Number of moles × molar mass of CaCl_2

= 2.657 moles × 110.98 g/mol

= 294.87 gm CaCl_2

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3 years ago

The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles

skelet666 [1.2K]

Answer:

k = $\frac{[HOCl]^2}{[Cl]^2}$

Explanation:

The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.

Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium

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