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WINSTONCH [101]
3 years ago
7

Calculate the mass of calcium chloride that contains 3.20 x 1024 atoms of chlorine.

Chemistry
1 answer:
frez [133]3 years ago
7 0

Answer:

294.87 gm  CaCl_2

Explanation:

The computation of the  mass of calcium chloride is shown below:

But before that following calculations need to be done

Number of moles of chlorine atom is

= 3.20 × 10^24 ÷ 6.022 × 10^23

= 5.314 moles

As we know that

1 mole CaCl_2 have the 2 moles of chlorine atoms

Now 5.341 mole chloride atoms would be

= 1 ÷ 2 × 5.314

= 2.657 moles

Now

Mass of CaCl_2 = Number of moles × molar mass of  CaCl_2

= 2.657 moles × 110.98 g/mol

= 294.87 gm  CaCl_2

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Answer:-  537 kJ of heat is released.

Solution:- For the given equation, \Delta H is -657 kJ and the coefficient of Cl_2 in the balanced equation is 2. It means 657 kJ of heat is released when 2 moles of chlorine are used. We need to calculate the heat released when 116 g of Cl_2 are used.

Grams of chlorine are converted to moles and then multiplied by the \Delta H value and divided by the coefficient of chlorine and the set could be shown using dimensional analysis as:

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If we use the correct sig figs then it needs to be round off to three sig figs as the given grams of chlorine has only three sig figs. So, 537 kJ of heat is released.

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