Question

Approximately what is the smallest detail observable with a microscope that uses ultraviolet light of frequency 1. 72 x 1015 hz? provide the solution: __________ x 10-7 m

Answer 1

The wavelength, which represents the size of the smallest detectable detail that uses ultraviolet light  , is calculated as follows: 3×$10^{8}$ / 1.72×$10^{15}$ or approximately 1.74×$10^{-7}$m.

The distance between the two positive, two negative, or two minimal points on the waveform is known as the wavelength of the wave. The following formula expresses the relationship between the frequency and wavelength of light:

f = c / λ

where, f = frequency of light

            c = speed of light

            λ = wavelength of light

Given data = f = 1.72×$10^{15}$Hz

Therefore, λ = 3×$10^{8}$ / 1.72×$10^{15}$

                  λ = 1.74×$10^{-7}$m

The wavelength, which represents the size of the smallest detectable detail that uses ultraviolet light  , is calculated as follows: 3×$10^{8}$ / 1.72×$10^{15}$ or approximately 1.74×$10^{-7}$m.

Learn more about light here;

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