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Elenna [48]
2 years ago
12

When one bumper car is still and the other one hits it (both cars have the same mass) what happens?

Physics
1 answer:
statuscvo [17]2 years ago
5 0

the first bump car will move

Explanation:

this is because as long as the other bumper car is coming with force, it mass changes and then , it is able to push the other one

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A 2.40 μC charge is subject to a 3.00 mN force due to an Electric Field. What is the magnitude of the Electric Field at the loca
Bezzdna [24]
<h2>Electric field at the location of the charge is 1250 N/C</h2>

Explanation:

Electric field is the ratio of force and charge.

Force, F = 3.00 mN = 3 x 10⁻³ N

Charge, q = 2.40 μC = 2.40 x 10⁻⁶ C

We have

                 E=\frac{F}{q}\\\\E=\frac{3\times 10^{-3}}{2.40\times 10^{-6}}\\\\E=1250N/C

Electric field at the location of the charge is 1250 N/C

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Why has the model of the atom changed over time?
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3 years ago
Measuring spoons are used when measuring<br>less than how much?​
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Measuring spoons are used when measuring less than 1/4 cup

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3 years ago
A 16 foot ladder is leaning against a wall. If the top of the ladder slides down the wall at a rate of 3 feet per second, how fa
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11.625

Explanation:

L = length of the ladder = 16 ft

v_{y} = rate at which top of ladder slides down = - 3 ft/s

v_{x} = rate at which bottom of ladder slides

y = distance of the top of ladder from the ground

x = distance of bottom of ladder from wall = 4 ft

Using Pythagorean theorem

L² = x² + y²

16² = 4² + y²

y = 15.5 ft

Also using Pythagorean theorem

L² = x² + y²

Taking derivative both side relative to "t"

0 = 2x\frac{\mathrm{d} x}{\mathrm{d} t} + 2y\frac{\mathrm{d} y}{\mathrm{d} t}

0 = x v_{x} + y v_{y}

0 = 4 v_{x} + (15.5) (- 3)

v_{x} = 11.625 ft/s

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3 years ago
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