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3 years ago

When one bumper car is still and the other one hits it (both cars have the same mass) what happens?

Physics

1 answer:

statuscvo [17]3 years ago

5 0

the first bump car will move

Explanation:

this is because as long as the other bumper car is coming with force, it mass changes and then , it is able to push the other one

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What the heck is friction

Anuta_ua [19.1K]

Answer:

Explanation:

Friction is a force that makes an object slow down. Not speed up, cause it to move, or occurs in a vacuum. Friction is often caused by the surface an object is moving on.

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3 years ago

Which vector shows the velocity of the yo-yo at this moment?

Helga [31]

The vector which shows the velocity of the yo-yo at this moment is A and is denoted as option A.

<h3>What is Velocity?</h3>

This is referred to the rate of change of distance with time and the unit is metre per seconds.

A shows the direction of motion is same as the direction of velocity and is the tangent at that particular point hence why it was chosen as the most appropriate choice.

Read more about Velocity here brainly.com/question/6504879

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2 years ago

Is this right?? Please help me. IT IS SOCIOLOGY!

inn [45]

Where is the picture???

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3 years ago

Define distance and displacement with illustration

Deffense [45]

Answer:

<h2>Distance</h2>

The length of the actual path travelled by a body is called distance travelled by a body.It is a scalar Quantity.It is measured in meter(m) in SI system.

<h2>Displacement</h2>

The shortest distance from initial position to the final position of a body is called displacement of the body.It is a vector Quantity.It is measured in meter(m) in SI system..

Please see the attached picture...

It is the example of distance and displacement....

Hope this helps...

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3 0

3 years ago

Two identical positive charges exert a repulsive force of 6.2 × 10−9 n when separated by a distance 3.7 × 10−10 m. calculate the

In-s [12.5K]

The electrostatic force between two charges is given by
$F=k \frac{q_1 q_2}{r^2}$
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is their separation

In this problem, the two charges are identical, so we can call them q1=q2=q, and the formula becomes
$F=k \frac{q^2}{r^2}$

Since we know the magnitude of the force and the separation between the two charges, we can re-arrange the equation to find the value of each charge:
$q= \sqrt{ \frac{Fr^2}{k} } = \sqrt{ \frac{(6.2 \cdot 10^{-9} N)(3.7 \cdot 10^{-10}m)^2}{8.99 \cdot 10^9 Nm^2C^{-2}} }=3.07 \cdot 10^{-19} C$

5 0

3 years ago