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I am Lyosha [343]
3 years ago
6

Help please hhjshwjsjejjenrhrhfhhfheisiw

Physics
1 answer:
DanielleElmas [232]3 years ago
4 0

Answer:

A

Explanation:

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A rock is tossed straight up from ground level with a speed of 22 m/s. When it returns, it falls into a hole 9.0 m deep. a. What
Vera_Pavlovna [14]

Answer:

(a) v_{f}=26.08m/s

(b) t=4.906seconds

Explanation:

We will take ground level as origin and upward is positive direction

the givens are

y_{i}=0\\y_{f}=-9.0m\\ v_{i}=22m/s

Part (a)

To find the final velocity we use the kinematic equation

So

(v_{f})^{2} =(v_{i})^{2} +2a(y_{f}-y_{i})\\(v_{f})^{2}=(22m/s)^{2}+2(-9.8m/s^{2} ) (-10-0)\\v_{f}=\sqrt{(22m/s)^{2}+2(-9.8m/s^{2} ) (-10-0)} \\v_{f}=26.08m/s

Part (b)

To find time of rock trip until it touches the ground we will use simple kinematic equation or simple motion equation

v_{f}=v_{i}+at\\t=\frac{v_{f}-v_{i}}{a}\\ t=\frac{(-26.08m/s)-(22m/s)}{-9.8m/s^{2} }\\t=4.906seconds

Notice that we substituted vf with negative sign because its direction is downwards

5 0
3 years ago
A convex lens has a focal length of 16.5 cm. Where on the lens axis should an object be placed in order to get a virtual, enlarg
alexandr402 [8]

Answer:

Object should be placed at a distance, u = 7.8 cm

Given:

focal length of convex lens, F = 16.5 cm

magnification, m = 1.90

Solution:

Magnification of lens, m = -\frac{v}{u}

where

u = object distance

v = image distance

Now,

1.90 = \frac{v}{u}

v = - 1.90u

To calculate the object distance, u by lens maker formula given by:

\frac{1}{F} = \frac{1}{u}+ \frac{1}{v}

\frac{1}{16.5} = \frac{1}{u}+ \frac{1}{- 1.90u}

\frac{1}{16.5} = \frac{1.90 - 1}{1.90u}

\frac{1}{16.5} = \frac{ 0.90}{1.90u}

u = 7.8 cm

Object should be placed at a distance of 7.8 cm on the axis of the lens to get virtual and enlarged image.

6 0
4 years ago
A kettle full of water is brought to a boil in a room with temperature 20°c. after 15 minutes the temperature of the water has
kogti [31]

Answer: The temperature after another 5 minutes is 68.5°c

Explanation: Please see the attachments below

4 0
3 years ago
How does the abundance of hydrogen and helium support the Big Bang Theory?
Blababa [14]

Answer:

Hydrogen and helium account for nearly all the nuclear matter in today's universe. This is consistent with the standard or "big bang" model. ... Basically , the hydrogen-helium abundance helps us to model the expansion rate of the early universe. If it had been faster, there would be more neutrons and more helium.

Explanation:

Google

3 0
3 years ago
Read 2 more answers
Light travels 186,282 miles in one second. A light year is the distance light travels in one year. It is about 4.3 light years t
deff fn [24]

Answer:

2.5278035226\times 10^{13}\ miles

1994.7944465 miles

46390568.5227 miles

125 ft

Explanation:

1\ ly=186282\times 365.25\times 24\times 60\times 60=5.8786128432\times 10^{12}\ mi

4.3\ ly=4.3\times 5.8786128432\times 10^{12}=2.5278035226\times 10^{13}\ miles

The distance is 2.5278035226\times 10^{13}\ miles

2000\ miles=0.01\ in

2.5278035226\times 10^{13}\times \dfrac{1}{2000}=1.2639017613\times 10^{10}\ LA\ to\ NY

Converting to inches

1.2639017613\times 10^{10}\times 0.01=126390176.13\ in/LA\ to\ NY

Converting to miles

126390176.13\times\dfrac{1}{5280\times 12}=1994.7944465\ inches/LA\ to\ NY

The distance is 1994.7944465 miles

5.8786128432\times 10^{17}\times \dfrac{1}{2000}\times 0.01\times\dfrac{1}{5280\times 12}=46390568.5227\ miles

The distance is 46390568.5227 miles

5.8786128432\times 10^{12}\times 15\times 10^{9}=8.8179192648\times 10^{22}

8.8179192648\times 10^{22}\times \dfrac{1}{5.8786128432\times 10^{17}}=150000\ MW\ dia

150000\dfrac{1}{100\times 12}=125\ ft

The distance is 125 ft

5 0
4 years ago
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