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azamat
2 years ago
5

explain, in therms of intermolecular forces, why greasy engine parts are better cleaned using petrol or kerosene as the solvent

than water.
Chemistry
1 answer:
coldgirl [10]2 years ago
6 0

Answer:

Grease is insoluble in water but soluble in kerosene

Explanation:

The molecules in grease are non polar molecules and so can not react with water which is polar to generate enough solvation energy. On the other hand kerosine is non polar so reacts with grease to generate enough solvation energy to dissolve it.

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What is the volume of 6.50g of gold if the density of gold is 19.3g/ml?
Jet001 [13]

Answer:

0.33 ml

Explanation:

Formula for density: p = m/V (where p is <em>density</em>, m is <em>mass</em> and V is <em>volume</em>)

So, by applying the above formula:

19.3 =  \frac{6.5}{v}

v = 0.33 \: ml

7 0
3 years ago
How does your reaction time to the voluntary action of your quadriceps in compare with your reaction time to the simple reaction
slava [35]

If we know what we are reading, reaction time to the simple reaction task in this project will be less than reaction time to the voluntary action of your quadriceps, however, if we are reading for the first time, reaction time to the simple reaction task in this project will be more than reaction time to the voluntary action of your quadriceps.

<h3><u>Explanation:</u></h3>

First, we need to know what is the reaction time. Reaction time is the amount of time it takes to respond to a stimulus. Now we will talk about voluntary and involuntary actions.

Voluntary action is an action that is thought of and consciously performed by the person. So we can say the person has full control over the situation. An involuntary action is one which occurs without the conscious choice of an organism. If the involuntary action occurred as a response to some stimulus it will be known as a reflex. If we compare the reaction time of voluntary action of our quadriceps and the simple reaction to the task given in the project, the reaction time could be less only if we have studied about the given question in the given task.

So the lines what we are reading will come to our mind involuntarily, but if we are talking about typing the answer the reaction time would be more as first, we have to form a structured sentence and then type it, so it will take more time.

8 0
3 years ago
THE RIGHT ANSWER WILL RECIEVE A BRAINLEST AND POINTS AND THANXS!!!
PSYCHO15rus [73]
1 - Chemistry is a branch of science focusing on elements, reactions, and chemicals.

2 - We study chemistry to learn more about these chemicals and elements and to discover new chemicals as well as to answer questions in life about reactions.

3 - Chemistry relates to our life in various ways, from the chemicals we inhale to the basic reactions in cooking and baking.

4 - The main branches of Chemistry are Physical, analytical, biochemistry, organic and inorganic chemistry.

Hope this helps!
3 0
3 years ago
What other objects are often arranged by their properties
blagie [28]

Answer:

Metaloids and metals.

8 0
3 years ago
A 1.0 mole sample of fluorine gas at 25 °C has an average molecular velocity of 415 m/s. What is the total KE of the gas sample?
Mariana [72]

The total kinetic energy of the gas sample is 3.3 KJ

<h3>What is kinetic energy? </h3>

This is the energy possessed by an object in motion. Mathematically, it can be expressed as:

KE = ½mv²

Where

  • KE is the kinetic energy
  • m is the mass
  • v is the velocity

<h3>How to determine the mass of the fluorine gas</h3>
  • Molar mass of fluorine gas = 38 g/mol
  • Mole of fluorine gas = 1 mole
  • Mass of fluorine gas = ?

Mass = mole × molar mass

Mass of fluorine gas = 1 × 38

Mass of fluorine gas = 38 g

<h3>How to determine the KE of the gas sample</h3>
  • Mass (m) = 38 g = 38 / 1000 = 0.038 Kg
  • Velocity (v) = 415 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.038 × 415²

KE = 3272.275 J

Divide by 1000 to express in kilojoule

KE = 3272.275 / 1000

KE = 3.3 KJ

Learn more about energy:

brainly.com/question/10703928

#SPJ1

4 0
2 years ago
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