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Sati [7]
3 years ago
15

Identify two acids and two bases that you use or come into contact with in an average week. Identify uses for each substance.

Chemistry
2 answers:
skelet666 [1.2K]3 years ago
4 0

Explanation:

Two acids we come into contact with in an average week

  1. Vinegar is an 10% solution of acetic acid (CH_3COOH)in water. Used in salad dressing and while cooking food. It has a sour taste.
  2. Citric acid present in fruits and vegetables like : lemons, orange, tomatoes etc. It is a weak organic acid with sour taste.

Two bases we come into contact with in an average week.  

  1. Baking soda (NaHCO_3) is used in baking food like: cakes, cookies, breads. Baking soda is one of the ingredient while baking breads and cakes.
  2. Caustic soda (NaOH) is used for preparation of detergents, papers , soaps etc. We use soaps and detergents for washing.
DaniilM [7]3 years ago
4 0
1 common acid that is used on a daily basis is Hydrochloric Acid in your stomach. It actives the enzyme pepsin into pepsinogen to degenerate proteins. Another acid is vinegar which is used in cooking and cleaning. 

A base I use on a daily basis is Tums as it has sodium bicarbonate, a common base used to neutralize stomach acids. Another one is ammonia which is used for hair and cleaning products. 
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2N2H4+ N2O4———3N2+4H2O SalmaKhan99 avatar How many grams of N2 gas will be formed by reacting 100g of N2H4 and 200g of N2 Kindly
Alona [7]

Answer:

131.26 g

Explanation:

From the balanced equation,

2 moles of N₂H₄reacts with 1 mole of N₂O₄ to give 3 moles of N₂

Now number of moles of N₂H₄ present in 100 g N₂H₄ is n = 100 g/molar mass N₂H₄.

Molar mass N₂H₄ = 2 × 14.01 g/mol + 1 × 4 g/mol = 28.02 g/mol + 4 g/mol = 32.02 g/mol

n₁ = 100/32.02 = 3.123 mol

Also

Now number of moles of N₂O₄ present in 200 g N₂O₄ is n = 200 g/molar mass N₂O₄.

Molar mass N₂O₄ = 2 × 14.01 g/mol + 16 × 4 g/mol = 28.02 g/mol + 64 g/mol = 92.02 g/mol

n₂ = 200/92.02 = 2.173 mol

Since the mole ratio of N₂H₄  to N₂O₄ is 2 : 1, We require 2 × 2.173 mol N₂H₄  to react with 2.173 mole N₂O₄  

Number of moles of N₂H₄ required is 4.346. But the number of moles of N₂H₄  present is 3.123 so N₂H₄  is the limiting reagent.

So, from the equation, 2 moles of N₂H₄ produces 3 moles of N₂

Therefore number of mole N₂ = 3/2 moles of N₂H₄ = 3/2 × 3.123 mol = 4.6845 mol

From n = m/M where n = number of moles of nitrogen gas = 4.6845 mol and M = molar mass of nitrogen gas = 28.02 g/mol and m = mass of nitogen gas.

m = nM = 4.6845 mol × 28.02 g/mol = 131.26 g

So the mas of nitrogen gas produced is 131.26 g

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