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3 years ago

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By how many times would you expect Al2(SO4)3 to depress the F.P of water compared to sucrose C12H22011 ?

1 answer:

34kurt3 years ago

5 0

Answer:

By how many times would you expect Al2(SO4)3 to depress the F.P of water compared to sucrose C12H22011 ?.

Explanation:

The freezing point of a pure solvent decreases further by adding a nonvolatile solute.

This is called depression in freezing point.

When an ionic solute is dissolved then the depression in the freezing point is proportional to the number of ions present in the solution.

In aluminum sulfate, there are five ions formed as shown below:

$Al_2(SO_4)_3(aq)->2Al^3^+(aq)+3SO_4^2^-(aq)$

But sucrose is a covalent compound and it does not undergo dissociation.

Hence, aluminum sulfate decreases the freezing point of water by five times compared to sucrose.

Explanation:

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Which is the term for an ion that has more protons than electrons

murzikaleks [220]

Answer:

The correct answer is cation. See the explanation below, please.

Explanation:

An atom with a net charge, either positive or negative, is called an ion. In the event that an atom loses an electron (or more), that is, it will have more protons than electrons, and its net charge will be positive, it will be called cation. In the opposite direction, if an atom gains electrons, it will have a negative net charge, called anion.

3 0

3 years ago

What type of compound is calcium oxide

DIA [1.3K]

A carbonate because the oxygen neutralizes the reactive coding of the calcium in its original form.

5 0

3 years ago

when you started the activity, the can was open to the air outside tge can. how did the air pressure inside the can compare to t

aliya0001 [1]

The air pressure inside the can is lower compared to that of outside air pressure.

Explanation:

In general, the air pressure of an already opened can will be the same as the outside pressure.
Since the can is evacuated and remain as vacuum, so there will be no pressure difference in it.
If the can opens, air inside the can push the top and escapes to the outside.
This is due to high pressure experienced outside the can compare to that of lower pressure inside the can and this may even cause can to collapse itself.

7 0

3 years ago

The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd

kenny6666 [7]

Answer:

The answer is " $= 0.078 \ kg \ H_2$ ".

Explanation:

calculating the moles in $CH_4 =\frac{PV}{RT}$

$=\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol$

Eqution:

$CH_4 +H_2O \to 3H_2+ CO \ (g)$

Calculating the amount of $H_2$ produced:

$= 12.9 \ mol CH_4 \times \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2$

So, the amount of dihydrogen produced = $0.078 \frac{kg}{s}$

5 0

3 years ago

How many moles of oxygen are in 52.5 grams of oxygen gas?

adell [148]

An oxygen gas is a diatomic molecule which means that each molecule is composed of 2 atoms. Its symbol is O2.

Each oxygen atom has a molar mass of 16 g/mol. The molar mass of oxygen gas is calculated below,
molar mass = 2 x (16 g/mol) = 32 g/mol

To determine the number of moles in 52.5 grams of oxygen, divide the given mass by the calculated molar mass.

n = 52.5 grams / (32 gram/ mol)
n = 1.64 moles

Thus, there are 1.64 moles of oxygen gas.

3 0

3 years ago