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sergeinik [125]
3 years ago
13

Increasing the concentration of a reactant shifts the position of a chemical equilibrium towards formation of more products. wha

t effect does adding a reactant have on the rates of the forward and reverse reactions?
a)There is no effect
b)Both the forward and reverse speed up by same amount
c)The foward reaction speeds up immeditaly
d)Forward reaction slows down
e)the forward reaction speeds up
f)more info needs to be given.
Chemistry
1 answer:
Natalija [7]3 years ago
4 0
<h2>The required "option is e)".</h2>

Explanation:

  • The Rate of formation of products depends on the concentration of reactants or the forward reaction increases on increasing the rate of the concentration.
  • There is no effect on the equilibrium rate when the concentration of reactants and products is constant.
  • Forward reaction slows down when the reactant concentration is decreased.
  • On increasing the amount or concentration of reactant the chemical  equilibrium shifts towards formation of more products.
  • Hence, the forward reaction speeds up.
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A compound that is composed of molybdenum (Mo) and oxygen (O) was produced in a lab by heating molybdenum over a Bunsen burner.
irakobra [83]
First, we determine the mass of each element from the data collected. We can get the mass of molybdenum Mo from the difference between the mass of crucible and molybdenum and the mass of crucible:
     Mass of molybdenum = 39.52 – 38.26 = 1.26 g Mo

We can calculate for the mass of molybdenum oxide from the difference between the mass of crucible and molybdenum oxide and the mass of crucible:
     Mass of molybdenum oxide = 39.84 – 38.26 = 1.58g 

We can now compute for the mass of oxygen O by subtracting the mass of molybdenum from the mass of molybdenum oxide:
     Mass of oxygen in molybdenum oxide = 1.58 – 1.26 = 0.32g O

To convert mass to moles, we use the molar mass of each element.
     1.26 g Mo * 1 mol Mo / 95.94 g Mo = 0.0131 mol Mo
     0.32 g O * 1 mol O / 15.999 g O = 0.0200 mol O

0.0131 mol is the smallest number of moles. We divide each mole value by this number:
     0.0131 mol Mo / 0.0131 = 1
     0.0200 mol O / 0.0131 = 1.53

Multiplying these results by 2 to get the lowest whole number ratio,
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5 0
3 years ago
Read 2 more answers
A sample of 4.0 L of nitrogen, at 1.2 atmospheres, is transferred to a 12 L container.
Zielflug [23.3K]

Answer:

The pressure will be 0.4 atm.

Explanation:

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them less times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:

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Boyle's law is expressed mathematically as:

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If you initially have the gas at a volume V1 and press P1, when the conditions change to a volume V2 and pressure P2, the following is satisfied:

P1*V1= P2*V2

In this case:

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  • P2= ?
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Replacing:

1.2 atm* 4 L= P2* 12 L

Solving:

P2=\frac{1.2 atm*4 L}{12 L}

P2= 0.4 atm

<u><em>The pressure will be 0.4 atm.</em></u>

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Protons, neutrons, and electrons.
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