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sergeinik [125]
3 years ago
13

Increasing the concentration of a reactant shifts the position of a chemical equilibrium towards formation of more products. wha

t effect does adding a reactant have on the rates of the forward and reverse reactions?
a)There is no effect
b)Both the forward and reverse speed up by same amount
c)The foward reaction speeds up immeditaly
d)Forward reaction slows down
e)the forward reaction speeds up
f)more info needs to be given.
Chemistry
1 answer:
Natalija [7]3 years ago
4 0
<h2>The required "option is e)".</h2>

Explanation:

  • The Rate of formation of products depends on the concentration of reactants or the forward reaction increases on increasing the rate of the concentration.
  • There is no effect on the equilibrium rate when the concentration of reactants and products is constant.
  • Forward reaction slows down when the reactant concentration is decreased.
  • On increasing the amount or concentration of reactant the chemical  equilibrium shifts towards formation of more products.
  • Hence, the forward reaction speeds up.
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Answer:

1

Explanation:

For an ideal gas, the average kinetic energy is given by:

Ek = (3/2)*n*R*T

Where n is the number of moles, R is the gas constant (8.31 J/mol*K), and T the temperature. The gases have the same number of moles, and the same temperature, so they will have the same average kinetic energy:

Ek = (3/2)*1*8.31*300

Ek =3739.5 J

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You will need to prepare 12 mL of 25% Sodium Phosphate Buffer (pH 4) solution for Activity 2. What volume of the stock Sodium Ph
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Assuming the concentration of stock solution is 50% sodium phosphate buffer solution, the volume of stock solution required is 6 mL and the volume of water required is 6 mL.

<h3>What volume of a stock Sodium phosphate buffer and water is needed to 12 mL of 25% sodium phosphate buffer of pH 4?</h3>

The process of preparing solutions from stock solutions of higher concentration is known as dilution.

Dilution is done with the aid of the dilution formula given below:

  • C1V1 = C2V2

where

  • C1 is the concentration of stock solution
  • V1 is the volume of stock solution required to prepare a diluted solution
  • C2 is the concentration of the diluted solution prepared
  • V2 is the final volume of the diluted solution

From the data provided:

C1 is not given

V1 is unknown

C2 = 25%

V2 = 12 mL

  • Assuming C1 is 50% solution

Volume of stock, V1, required is calculated as follows:

V1 = C2V2/C1

V1 = 25 × 12 /50

V1 = 6 mL

Therefore, the volume of stock solution required is 6 mL and the volume of water required is 6 mL.

Learn more about dilution formula at: brainly.com/question/7208546

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