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Mumz [18]
2 years ago
14

Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight camping stoves. Suppose a li

ghter contains 5.50 mL of butane (d = 0.579 g/mL). (b) How many moles of H₂O form when all the butane burns?
Chemistry
1 answer:
exis [7]2 years ago
7 0

4.60 g of  of H₂O form when all the butane burns.

<h3>What is butane ?</h3>

One of the smallest liquid streams frequently created in a refinery is butane. Ten hydrogen atoms and four carbon atoms make up the butane molecule. Typically, butane is either marketed as a finished product or is blended into LPG or gasoline in tiny quantities.

It is frequently employed as a fuel for portable stoves and cigarette lighters, as a propellant in aerosols, as a heating fuel, as a refrigerant, and in the production of a broad variety of goods. Liquefied petroleum gas and butane both exist (LPG).

Butane has a low level of toxicity. In butane misuse, high exposure concentrations can be anticipated. Central nervous system (CNS) and cardiac consequences are the most frequently seen effects in cases of misuse.

To learn more about butane from the given link:

brainly.com/question/14818671

#SPJ4

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3 years ago
What is the composition, in atom percent, of an alloy that contains a) 45.5 lbm of silver, b) 83.7 lbm of gold, and c) 6.3 lbm o
lyudmila [28]

Answer:

\% atAg=44.6\%\\\% atAu=44.9\%\\\% atCu=10.5\%

Explanation:

Hello,

In this case, for computing the atom percent, one must obtain the number of atoms of silver, gold and copper as shown below:

atomsAg=45.5lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{107.87gAg}*\frac{6.022x10^{23}atomsAg}{1molAg}=1.15x10^{26}atomsAg\\atomsAu=83.7lbm*\frac{453.59g}{1lbm}*\frac{1molAu}{196.97gAu}*\frac{6.022x10^{23}atomsAu}{1molAu}=1.16x10^{26}atomsAu\\atomsCu=6.3lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{63.55gCu}*\frac{6.022x10^{23}atomsCu}{1molCu}=2.71x10^{25}atomsCu

Thus, the atom percent turns out:

\% atAg=\frac{1.15x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.6\%\\\% atAu=\frac{1.16x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.9\%\\\% atCu=\frac{2.71x10^{25}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =10.5\%

Best regards.

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