Question

1.) A balloon contains 0.126 mol of gas and has a volume of 2.74 L .

Answer 1

Answer:

• Problem 1: 5.44L

• Problem 2: 479mL

Explanation:

Problem 1.

a) Data:

• n₁ = 0.126 mol
• V₁ = 2.74 L
• n₂ = 0.126mol + 0.124mol
• V₂ = ?
• Conditions: constant temperature and pressure

b) Physical principles:

The volume occupied by a gas, when the temperature and pressure remain unchanged, is proportional to the number of moles of gas.

          $\dfrac{n_1}{V_1}=\dfrac{n_2}{V_2}$

c) Solution:

Solve for V₂ , substitute and compute:

        $V_2=n_2\times\dfrac{V_1}{n_1}\\ \\\\ V_2=(0.126mol+0.124 mol)\times \dfrac{2.74L}{0.126mol}\\ \\ \\ V_2=5.44L$

Problem 2.

a) Data:

• n₁ = 0.547mol
• V₁ = 295 mL
• V₂ = ?
• n₂ = 0.547mol + 0.342 mol
• Conditions: constant temperature and pressure

b) Physical principles:

The same as above: the volume occupied by a gas, when the temperature and pressure remain unchanged, is proportional to the number of moles of gas.

          $\dfrac{n_1}{V_1}=\dfrac{n_2}{V_2}$

c) Solution:

Solve for V₂ , substitute and compute:

        $V_2=n_2\times\dfrac{V_1}{n_1}\\ \\\\ V_2=(0.547mol+0.342 mol)\times \dfrac{295mL}{0.547mol}\\ \\ \\ V_2=479mL$