Question

For the skeletal chemical equation BF3(g) + NaH(s) → B2H6(g) + NaF(s) what is the coefficient of B2H6 in the balanced equation? (Balance the equation with the smallest possible whole number coefficients.)

Answer 1

Answer:

Coefficient in front of the $B_2H_6$  in the balanced equation - 1

Explanation:

The unbalanced Chemical equation is shown below as:-

$BF_3+NaH\rightarrow B_2H_6+NaF$

On the left hand side,  

There are 1 boron atom and 3 fluorine atoms and 1 sodium and hydrogen atoms.

On the right hand side,  

There are 2 boron atoms and 6 hydrogen atoms and 1 sodium and fluorine atoms.

Thus,  

leftside, $BF_3$ must be multiplied by 2 to balance boron and right side, $NaF$ must be multiplied by 6 to balance fluorine. Left side, $NaH$ must be multiplied by 6 to balance sodium and hydrogen atoms.

Thus, the balanced reaction is:-

$2BF_3+6NaH\rightarrow B_2H_6+6NaF$

Coefficient in front of the $B_2H_6$  in the balanced equation - 1

Answer 2

Answer:

Coefficient of $B_2H_6$ in the balanced equation is 1.

Explanation:

Chemical equation given is:

$BF_3+NaH-->B_2H_6+NaF$

Clearly the equation is not balanced.

Step 1:

There are six hydrogens in the RHS.Hence we make number of hydrogens as 6 in LHS by writing 6NaH.

Step 2:

Now the number of Na in LHS becomes 6.To balance it,we write 6NaF in the RHS.

Step 3:

Now there are only 3 flourines in LHS.So we write 2BF3 to make the number of flourine atoms 6.

Final balanced equation:

$2BF_3+6NaH-->B_2H_6+6NaF$

Coefficient of B2H6 is 1.