Yes it is. Copper is the same mass and volume. Plus all pennies are made of copper
Explanation:
A.
In a diprotic acid, 2 moles of H+ ions is released. Therefore, number of moles of H+ in a diprotic acid = 2 × number of moles of H+ of monoprotic acid.
B.
Equation of the reaction
2NaOH + H2SO4 --> Na2SO4 + 2H2O
Number of moles of H2SO4 = molar concentration × volume
= 0.75 × 0.0105
= 0.007875 moles.
By stoichiometry, since 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, number of moles of NaOH = 2 × 0.007875
= 0.01575 moles.
Molar concentration of NaOH = number of moles ÷ volume
= 0.01575 ÷ 0.0175
= 0.9 M of NaOH.
1. D
2. DR
3. SR
4. DR
5. C
6. SR
7. S
8. D
10. C
10H₂ + 5O₂ → 10H₂O
Explanation:
This problem deals with balancing of chemical equations. In balancing chemical equations, the law of conservation of mass must be followed. This states that:
"In a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".
This meaning of this is that; the number of atoms on each side of the expression must be the same.
2H₂ + O₂ → 2H₂O
let us check is the equation above is balanced;
2H₂ + O₂ → 2H₂O
Elements reactant product
H 4 4
O 2 2
We can see vividly that the equation is balanced;
Now; if we have 5 oxygen gas, we multiply the equation through by 5:
5 x ( 2H₂ + O₂ → 2H₂O )
⇒ 10H₂ + 5O₂ → 10H₂O
Elements reactant product
H 20 20
O 10 10
learn more:
Balanced equation brainly.com/question/11102790
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Answer:

Explanation:
Molarity is a measure of concentration in moles per liter.

The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.
- molarity= 1.2 mol NaNO₃/L
- liters of solution=0.25 L
- moles of solute =x

We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.


The units of liters cancel, so we are left with the units moles of sodium nitrate.


There are 0.3 moles of sodium nitrate.