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tensa zangetsu [6.8K]
3 years ago
9

From the amount of NaOH added at the 1st equivalence point, calculate the original molarity of the acid. Carry out the same calc

ulation based on the amount of NaOH added at the 2nd equivalence point. Label all parts of your work clearly.
Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer:

Molarity of acid, Ca = Cb*Vb*A/Va*B

Explanation:

Using H2SO4 as acid, the reaction is as follow:

2NaOH  +  H2SO4 ⇒ Na2SO4  +  2H2O

Volume of acid = Va; Volume of base = Vb, Molar concentration of  acid = Ca; Molar concentration of base = Cb; Molarity of acid = A and Molarity of base = B

Ca*Va/Cb*Vb =A/B

∴ Ca = Cb*Vb*A/Va*B

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<h3>What is Density ?</h3>

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Disclaimer: The given question is incomplete on the portal. Here is the complete question.

Question: The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v)

density = \frac{\text{Mass}}{\text{Volume}}  or d = \frac{m}{V}

Considering that mass and volume are both extensive properties, explain why their ratio, density is intensive.

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