Explanation:
Given parameters:
Density of silver = 10.5g/cm³
Volume of silver given = 4mL
Unknown:
Mass of silver = ?
Solution:
Density of a substance can be expressed as its mass per unit volume
Density = 
we need to convert our volume to cm³ from mL;
1cm³ = 1mL
So 4mL = 4cm³
input the values in;
Mass = density x volume = 10.5 x 4 = 42g
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Answer:
No, they don't because of fact some way more than the other even if it's the same type of element.
Explanation:
There are two types of element weight I think.
Answer:
123 g/mol
Explanation:
Let's consider the neutralization reaction.
H₂Z(aq) + 2 NaOH(aq) → Na₂Z(aq) + 2 H₂O(ℓ)
The moles of NaOH that reacted are:
The molar ratio of H₂Z to NaOH is 1:2. The moles of H₂Z that reacted are:
The molar mass of H₂Z is:
Answer:
The correct answer is 1.89130 × 10⁻² g per ml.
Explanation:
Based on the given information, the volume of the water sample is 46 ml, the temperature given is 21 degree C. Weight of the compound mineral X is 0.87 grams obtained post evaporating, washing, and drying of the sample. Yes, on the basis of the given information, one can find the solubility of compound X in water at 21 degree C.
As 46 ml of water comprise 0.87 grams of the mineral compound X. Therefore, 1 ml of the water sample will comprise,
= 0.87/46 g of X
= 1.89130 × 10⁻² grams
Hence, the solubility of the compound X in the sample of water is 1.89130 × 10⁻² gram per ml.
Q1)
the balanced equation is ;
<span>SiO</span>₂<span>(s) + 3C(s) → SiC(s) + 2CO(g)
stoichiometry of SiO</span>₂ to C is 1:3
mass of SiO₂ reacted - 15.70 g
molar mass of SiO₂ - 60 g/mol
Number of SiO₂ moles that reacted - 15.70 g / 60 g/mol = 0.26 mol
Then the number of C moles that reacted - 0.26 mol x3 = 0.78 mol
Mass of C required - 0.78 mol x 12 g/mol = 9.36 g
Q2)
Stoichiometry of SiO₂ to SiC is 1:1
SiO₂ is the limiting reactant, therefore amount of product formed depends on amount of SiO₂ reacted.
Number of SiO₂ moles reacted - 152 g/ 60 g/mol = 2.53 mol
Therefore number of SiC moles formed - 2.53 mol
molar mass of SiC - 40 g/mol
Mass of SiC formed - 2.53 mol x 40 g/mol = 101.2 g
Q3)
Stoichiometry of C to CO is 3:2
Molar mass of CO - 28 g/mol
Number of CO moles formed - 42.2 g / 28 g/mol = 1.5 mol
2 mol of CO formed when - 3 mol of C reacts
When 1.5 mol of CO are formed - 3/2 x 1.5 mol = 2.25 mol of C reacted
therefore 2.25 mol of C reacted
Mass of C reacted - 2.25 mol x 12 g/mol = 27 g
