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tensa zangetsu [6.8K]
3 years ago
9

From the amount of NaOH added at the 1st equivalence point, calculate the original molarity of the acid. Carry out the same calc

ulation based on the amount of NaOH added at the 2nd equivalence point. Label all parts of your work clearly.
Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer:

Molarity of acid, Ca = Cb*Vb*A/Va*B

Explanation:

Using H2SO4 as acid, the reaction is as follow:

2NaOH  +  H2SO4 ⇒ Na2SO4  +  2H2O

Volume of acid = Va; Volume of base = Vb, Molar concentration of  acid = Ca; Molar concentration of base = Cb; Molarity of acid = A and Molarity of base = B

Ca*Va/Cb*Vb =A/B

∴ Ca = Cb*Vb*A/Va*B

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Acetylene is hyrodgenated to form ethane. The feed to the reactor contains 1.60 mol H2/mol C2H2. The reaction proceeds to comple
Black_prince [1.1K]

Answer:

Explanation:

C₂H₂     +   2H₂   =     C₂H₆

1 mole     2 mole        1 mole

Feed of reactant is 1.6 mole H₂ / mole C₂H₂

or 1.6 mole of H₂ for 1 mole of C₂H₂

required ratio as per chemical reaction written above

2 mole of  H₂ for 1 mole of C₂H₂

So H₂ is in short supply . Hence it is limiting reagent .

1.6 mole of H₂ will react with half of 1.6 mole or .8 mole of C₂H₂ to form .8 mole of C₂H₆

a )Calculate the stoichiometric reactant ratio =  mole H₂ reacted/mole C₂H₂ reacted

= 1.6 / .8 = 2 .

b )

yield ratio = mole C₂H₆ formed / mole H₂ reacted ) = 0.8 / 1.6 = 1/2 = 0.5 .

4 0
3 years ago
If a Hh mom has an offspring with a hh dad, what is the probability that the offspring will have a dominant phenotype?
lisov135 [29]

Answer:

I think 50%

Explanation:

im not really sure

6 0
2 years ago
What does a positive value of A Gº mean for a reaction?
Airida [17]

Answer:

D

Explanation:

If delta G at standard conditions is positive, then the reaction will always be nonspontaneous in the forward direction.

3 0
2 years ago
The mass of sodium chloride in (g) is 14.19 The volume of ammonia solution in (mL) is 36.15 Calculate the following: What is the
Svetach [21]

This is an incomplete question, here is a complete question.

A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M ammonia solution at ice temperature, and carbon dioxide is bubbled in. Assume that sodium bicarbonate is formed util the limiting reagent is entirely used up. the solubility of sodium bicarbonate in water at ice temperature is 0.75 mol per liter. Also assume that all the sodium bicarbonate precipitated is collected and converted quantitatively to sodium carbonate.

Data to be used for calculating the results

-The mass of sodium chloride in (g) is 14.19

-The volume of ammonia solution in (mL) is 36.15

Calculate the following: What is the theoretical yield of sodium bicarbonate in grams?

Answer : The theoretical yield of sodium bicarbonate in grams is, 20.4 grams.

Explanation :

First we have to calculate the moles of NaCl and NH_3.

\text{ Moles of }NaCl=\frac{\text{ Mass of }NaCl}{\text{ Molar mass of }NaCl}=\frac{14.19g}{58.5g/mole}=0.243moles

\text{ Moles of }NH_3=\text{ Concentration of }NH_3\times \text{ Volume of solution}=4.00M\times 0.3615L=1.446moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

NH_3+NaCl+CO_2+H_2O\rightarrow NaHCO_3+NH_4Cl

From the balanced reaction we conclude that

As, 1 mole of NaCl react with 1 mole of NH_3

So, 0.243 mole of NaCl react with 0.243 mole of NH_3

From this we conclude that, NH_3 is an excess reagent because the given moles are greater than the required moles and NaCl is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of NaHCO_3

From the reaction, we conclude that

As, 1 mole of NaCl react to give 1 mole of NaHCO_3

So, 0.243 moles of NaCl react to give 0.243 moles of NaHCO_3

Now we have to calculate the mass of NaHCO_3

\text{ Mass of }NaHCO_3=\text{ Moles of }NaHCO_3\times \text{ Molar mass of }NaHCO_3

Molar mass of sodium bicarbonate = 84 g/mol

\text{ Mass of }NaHCO_3=(0.243moles)\times (84g/mole)=20.4g

Thus, the theoretical yield of sodium bicarbonate in grams is, 20.4 grams.

4 0
3 years ago
Compare the first ionization energy of sodium to that of potassium
stellarik [79]

Answer:

Sodium is higher than Potassium in thesame group

Explanation:

Sodium and potassium are the elements present in the first group of the periodic table. In group, atomic size increases from top to bottom this implies that even atomic radius increases. This causes less attraction force by nucleus on the electrons of outermost orbit of the atom and hence reduces the first ionisation energy, which is the energy required to remove the electron from the outermost orbit of an atom. So, as potassium is below sodium in the group, sodium has greater ionisation energy than potassium

3 0
3 years ago
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