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NeTakaya
1 year ago
13

BD bisects ZABC. Solve for x and find mABC. m/ABD = 11x - 10, m/CBD = 8x + 2

Mathematics
1 answer:
Tamiku [17]1 year ago
7 0

The value of x is 4 and the value of ∠ABC is 68°.

To solve this problem we first have to understand the concept of an angle bisector. Angle bisector is a straight line passes through the vertex of an angle dividing the angle in two equal angles.

According to the condition BD bisects ∠ABC

Therefore the two angles formed by the angle bisector are ∠ABD and ∠CBD.

The angle value of these two angles are equal.

Given:

m∠ABD=11x-10

m∠CBD=8x+2

Therefore from the above condition:

m∠ABD=m∠CBD

Substituting the values we get:

11x-10=8x+2

Solving the linear equation to find the value of x.

or,11x-10=8x+2\\or,11x-8x=2+10\\or,3x=12\\or,x=4

Now let us find the value of ∠ABC

m∠ABC=m∠ABD+m∠CBD

or,∠ABC=11x-10+8x+2

or,∠ABC=19x-8

Substituting the value x=4 in the equation we get:

m∠ABC=19×4-8

or,m∠ABC=68°

Therefore we can conclude that the value of xis 4 and the value of ∠ABC is 68°.

To learn more about angle bisectors:

brainly.com/question/12896755

#SPJ9

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LekaFEV [45]

Answer:

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Step-by-step explanation:

First, find the unit rate:

12/3= 4

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4*50= 200

Hope this helps!

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2 years ago
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How do you find the cube root
zvonat [6]
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</span>Example Cube Roots:<span>The 3rd root of 64, or 64 radical 3, or the cube root of 64 is written as \( \sqrt[3]{64} = 4 \).The 3rd root of -64, or -64 radical 3, or the cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).The cube root of 8 is written as \( \sqrt[3]{8} = 2 \).The cube root of 10 is written as \( \sqrt[3]{10} = 2.154435 \).</span>

The cube root of x is the same as x raised to the 1/3 power. Written as \( \sqrt[3]{x} = x^{\frac{1}{3}} \). The common definition of the cube root of a negative number is that <span>
(-x)1/3</span> = <span>-(x1/3)</span>.[1] For example:

<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span><span>

</span>This was not copied from a website or someone else. This was from my last year report.
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f -64, or -64 radical 3, or the cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).The cube root of 8 is written as \( \sqrt[3]{8} = 2 \).The cube root of 10 is written as \( \sqrt[3]{10} = 2.154435 \).</span>

The cube root of x is the same as x raised to the 1/3 power. Written as \( \sqrt[3]{x} = x^{\frac{1}{3}} \). The common definition of the cube root of a negative number is that <span>
(-x)1/3</span> = <span>-(x1/3)</span>.[1] For example:

<span>The cube root of -27 is written as \( \sqrt[3]{-27} = -3 \).The cube root of -8 is written as \( \sqrt[3]{-8} = -2 \).The cube root of -64 is written as \( \sqrt[3]{-64} = -4 \).</span>
6 0
3 years ago
The measure ∠BQS of is 80°. What is the m∠NQS? 42° 48° 128° 32°
fomenos

Answer:

m<NQS = 32°

Step-by-step explanation:

Given:

m<BQS = 80°

m<BQN = 48°

Required:

m<NQS

SOLUTION:

Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.

Therefore:

m<BQN + m<NQS = m<BQS (angle addition postulate)

48° + m<NQS = 80° (substitution)

m<NQS = 80 - 48° (Subtraction of 48 from each side)

m<NQS = 32°

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Answer:

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Step-by-step explanation:

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3 years ago
Quadrilateral ABCD is dilated by a scale factor of 1 over 3 centered around (1, 2). Which statement is true about the dilation?
Sonbull [250]

<em>Note: Since you missed to add the figure. So, after a little research I am kind of able to find the figure and hence, assuming it as a reference. Hence, I am attaching the figure and solution of that figure is also visible in the same figure.</em> Please check the attached figure (a)

Answer:

Segment B'D' will be parallel to segment BD and will be shorter than segment BD. Please see the attached figure (a) for better understanding.

Step-by-step explanation:

As we know that there are certain rules when a quadrilateral is dilated by a certain scale centered around a certain point.

So,

Let suppose P(a, b) is the point.

The dilation rule by a scale factor of 1 over 3 or (1/3) centered around (1, 2) is

P(a, b) → P(\frac{x+2}{3}, \frac{y+4}{3})

Hence,

            A(1, 2) → A'(1, 2)

            B(2, 3) → B'(4/3, 7/3)

            C(4, 2) → C'(2, 2)

             D(2, 1) → D'(4/3, 5/3)

The attached figure show that if we draw the all these points in the coordinate plan i.e. A(1, 2), B(2, 3), C(4, 2), D(2, 1) and A'(1, 2), B'(4/3, 7/3), C'(2, 2), D'(4/3, 5/3), we can determine that Segment B'D' will be parallel to segment BD and will be shorter than segment BD.

<em>Keywords: dilation, quadrilateral, segment</em>

<em> Learn more about dilation from brainly.com/question/7569824</em>

<em> #learnwithBrainly</em>

7 0
3 years ago
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