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podryga [215]
11 months ago
13

If the change in velocity is 60 miles per hour in 3 seconds, what is the change in velocity per second?

Physics
1 answer:
Alexandra [31]11 months ago
3 0

Answer:

20 miles/hour

Explanation:

60 / 3 =  20 miles/hour

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Which of the following leads to new discoveries and new theories?
Fynjy0 [20]

)scientific knowledge

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A rock that has magnetic properties is
Dahasolnce [82]

Answer: lodestone

Explanation:

ITS LODESTONE

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2 years ago
A baseball with a mass of 0.15 kilograms collides with a bat at a speed of 40 meters/second. The duration of the collision is 8.
Vedmedyk [2.9K]

Answer: 1687.5 N

Explanation:

From the second law of motion given by Newton, Force is the rate change of momentum.

F = \frac{dp}{dt}=\frac {m dv}{dt} = \frac{m (v_f-v_i)}{dt}

Mass of the baseball, m = 0.15 kg

Initial velocity, v_i=-40 m/s (negative because direction of initial velocity is opposite to the final velocity)

Final velocity, v_f=50 m/s

The duration of collision, dt= 8.0 \times 10^{-3} s

Force, F = \frac{0.15 kg (50-(-40) m/s)}{8.0 \times 10^{-3} s}=1687.5 N

Hence, the value of force is 1687.5 N.

8 0
3 years ago
Course hero N4M.6 A board has one end wedged under a rock having a mass of 380 kg and is supported by another rock that touches
aleksandrvk [35]

Answer:

Therefore it is save to carry a 62kg adult

Explanation:

From the question we are told that:

Mass m=380kg

Height of supporting Rock X=85cm

Length of BoardL_r=4.5m

Mass of board M_b=22kg

Mass of adult M_a=62  

Generally the moment of balance about wedge part about  is mathematically given by

N -Q + R = Mg + mg

0.85*N - Mg*2.25 - mg*(2.25 + x) = 0

0.85*N  = + Mg*2.25 + mg*(2.25 + x)

where

N+R=4547

therefore

N = 570.70588 + 1608.3529 + 714.823 x

if N=0 at fallen person

x=3.04m

Therefore it is save to carry a 62kg adult

8 0
2 years ago
What magnitude charge creates a 1.0 n/c electric field at a point 1.0 m away?
Stolb23 [73]

Answer:

1.1\cdot 10^{-10}C

Explanation:

The electric field produced by a single point charge is given by:

E=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem, we have

E = 1.0 N/C (magnitude of the electric field)

r = 1.0 m (distance from the charge)

Solving the equation for q, we find the charge:

q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C

8 0
2 years ago
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