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Contact [7]
3 years ago
14

Where in the motion is the magnitude of the force from the spring on the object zero? Where in the motion is the magnitude of th

e force from the spring on the object a maximum? Where in the motion is the magnitude of the net force on the object zero? Where in the motion is the magnitude of the net force on the object a maximum?
Physics
1 answer:
kkurt [141]3 years ago
8 0

<em></em>

Answer:

1. The magnitude of the force from the spring on the object is zero on <em>Equilibrium.</em>

2. The magnitude of the force from the spring on the object is a maximum on <em>The top and bottom.</em>

3. The magnitude of the net force on the object is zero on <em>The Bottom.</em>

4. The magnitude of the force on the object is a maximum on <em>the Top.</em>

Explanation:

<em>1. Because the change in position delta X is zero.</em>

<em>2. Because of delta X.</em>

<em>3. Beacuse, the force of gravity and the force of the spring oppose each other to keep the block at rest, away from the equilibrium position.</em>

<em>4. Because, the force of the spring from compressiom and the force of gravity both act on the mass.</em>

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Recall the topography of the Sierra Nevada Mountains east of California's central valley. Which of the following locations would
marysya [2.9K]

Answer:

3. western slope

Explanation:

If we investigate the physical features (such as natural and artificial features) of the Sierra Nevada Mountains located at the California's central valley eastern part, the western slope has the highest value of the precipitation level yearly. This is due to the location of the slope and the relevant conditions such as temperature and humidity.

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3 years ago
1. (30 pts) Let x(t) = cos(πt/2) be a continuous-time signal,
posledela

Given that the function of the wave is f(x) = cos(π•t/2), we have;

a. The graph of the function is attached

b. 4 units of time

c. Even

d. 4.935 J/kg

e. 1.234 W/kg

<h3>How can the factors of the wave be found?</h3>

a. Please find attached the graph of the signal created with GeoGebra

b. The period of the signal, T = 2•π/(π/2) = <u>4</u>

c. The signal is <u>even</u>, given that it is symmetrical about the y-axis

d. The energy of the signal is given by the formula;

\frac{1}{2}  \cdot  \mu^{2} \cdot \omega ^{2}  \cdot \:  {a}^{2}  \times  \lambda

Which gives;

E = 0.5 × 1.571² × 1² × 4 = <u>4.935 J/kg</u>

e. The power of the wave is given by the formula;

E = 0.5 × 1.571² × 1² × 4 × 0.25 = <u>1.234 W/</u><u>kg</u>

Learn more about waves here:

brainly.com/question/14015797

8 0
2 years ago
You and a friend each hold a lump of wet clay. Each lump has a mass of 30 grams. You each toss your lump of clay into the air, w
Vesna [10]

Answer:

\ \text{m/s}

Explanation:

u_1 = Velocity of one lump = 3x+3y-3z

u_2 = Velocity of the other lump = -4x+0y-4z

m = Mass of each lump = 30\ \text{g}

The collision is perfectly inelastic as the lumps stick to each other so we have the relation

mu_1+mu_2=(m+m)v\\\Rightarrow m(u_1+u_2)=2mv\\\Rightarrow v=\dfrac{u_1+u_2}{2}\\\Rightarrow v=\dfrac{3x+3y-3z-4x+0y-4z}{2}\\\Rightarrow v=-0.5x+1.5y-3.5z=\ \text{m/s}

The velocity of the stuck-together lump just after the collision is \ \text{m/s}.

4 0
2 years ago
The pressure inside a blimp is 506 Pa, if the area is 3,000cm2 then what is the force? ​
Zarrin [17]

Answer:

<h2>151.8 N</h2>

Explanation:

The force acting on the blimp can be found by using the formula

<h3>f = p × a</h3>

p is the pressure

a is the area

3000 cm² = 0.3 m²

From the question we have

f = 506 × 0.3

We have the final answer as

<h3>151.8 N</h3>

Hope this helps you

6 0
2 years ago
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