Question

Write a balanced, net ionic equation for the precipitation reaction of cacl2 and cs3po4 in an aqueous solution. Remember to include the proper physical states and charges of ions. When writing ions, if a charge number is not 1, place the charge number before the charge sign. If a charge sign is 1, do not include the charge number in the formula.

Answer 1

The balanced chemical equation for the precipitation reaction of CaCl₂ and Cs₃PO₄ in an aqueous solution is:

3Ca²⁺(aq) +  2PO₄³⁻(aq) → Ca₃(PO4)₂(s)

The insoluble salts Ca₃(PO4)₂ and CsCl are created when the calcium ion in CaCl₂ interacts with the phosphate ion in Cs₃PO₄. CaCl₂(aq) + CsO₄(aq) Ca₃(PO4)₂(s) + CsCl.  

The unbalanced reaction is:

CaCl₂(aq) + Cs₃PO₄(aq) → Ca₃(PO4)₂(s) + CsCl(aq)

To balance the calcium:

3CaCl₂(aq) + Cs₃PO₄(aq) → Ca₃(PO4)₂(s) + CsCl(aq)

The chlorides:

3CaCl₂(aq) + Cs₃PO₄(aq) → Ca₃(PO4)₂(s) + 6CsCl(aq)

And the Cs:

3CaCl₂(aq) + 2Cs₃PO₄(aq) → Ca₃(PO4)₂(s) + 6CsCl(aq)

This is the balanced reaction, the ionic equation is:

3Ca²⁺(aq) + 6Cl⁻(aq) + 6Cs⁺(aq) + 2PO4³⁻(aq) → Ca₃(PO4)₂(s) + 6Cs⁺(aq) + 6Cl⁻(aq)

Subtracting the ions that don't react:

3Ca²⁺(aq) +  2PO4³⁻(aq) → Ca3(PO4)2(s)

This is the net ionic equation

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