Data Given:
Volume = V = 44.8 L
Standard Pressure = P = 1 atm
Standard Temperature = T = 273 K
According to Ideal Gas Equation,
P V = n R T
Solving for n,
n = P V / R T
Putting values,
n = (1 atm × 44.8 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 273 K)
n = 1.99 mol
Now, calculating for mass,
n = Mass / M.mass
Or,
Mass = n × M.mass
Mass = 1.99 mol × 28 g.mol⁻¹
Mass = 55.72 grams
Answer:
Number of moles = 558.46 mol
Explanation:
Density = 804 g/L
Molecular formula = C13H28
Molar mass = 184.37 g/mol
Distance = 3680 km
Rate = 3.48 L of fuel per 100. km
Volume is calculated as follow;
3.48 = 100
x = 3680
x = 3680 * 3.48 / 100
x = 128.064 L
Number of moles = Mass / Molar mass
Mass = Density * Volume
Mass = 804 * 128.064 = 102963.456 g
Number of moles = 102963.456 / 184.37
Number of moles = 558.46 mol
Most likely an amphibian or reptile
Explanation:
The reaction is as follows:
2Mg(s) + O2(g) ---> 2MgO(s)
and the researcher said that 32 g of MgO was produced.
Stoichiometry:
28 g Mg × (1 mol Mg/24.305 g Mg) = 1.15 mol Mg
15 g O2 × (1 mol O2/15.999 g O2) = 0.938 mol O2
1.15 mol Mg × (2 mol MgO/2 mol MgO) = 1.15 mol MgO
1.15 mol MgO × (40.3044 g MgO/1 mol MgO) = 46.6 g MgO
0.938 mol O2 × (2 mol MgO/1 mol O2) = 1.88 mol MgO
1.88 mol MgO × (40.3044 g MgO/1 mol MgO = 75.6 g MgO
Based on these numbers, the amount of product after the reaction is much less than expected so these results don't seem to support the law of conservation of matter.
Answer:
none of the above
Explanation:
because all of them are unstable
