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Alex Ar [27]
3 years ago
13

How many H atoms are in 6.43g x 10^24 molecules of water

Chemistry
1 answer:
kow [346]3 years ago
5 0

Answer:

12.86\times 10^{24} atoms of hydrogen

Explanation:

The molecular formula for a water molecule is H_2O.

From the above formula, we can conclude that 1 molecule of water contains 2 atoms of hydrogen and 1 atom of oxygen.

There are 6.43\times 10^{24} molecules of water.

1 molecule of water = 2 atoms of hydrogen.

∴ 6.43\times 10^{24} molecules of water = 2\times 6.43\times 10^{24}=12.86\times 10^{24} atoms of hydrogen.

Therefore, there are 12.86\times 10^{24} atoms of hydrogen in 6.43\times 10^{24} molecules of water.

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E. The element 231/90Th decays to 231/91 Pa. Use the laws of conservation of charge and nucleon number to determine the decay pa
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Answer:

A negatron emission

Explanation:

We know that radioactivity orginates from instability of the nucleus. When the nucleus is unstable, radioactive emissions are produced in the form of any of these rays:

> Alpha particle emisson

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In balancing nuclear reactions we make sure that the charges on both sides must be conserved and that the mass number and atomic numbers conserved too. This means that the sum of mass number and atomic numbers on both side of the reaction must be equal.

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For the given radioactive reaction:

²³¹₉₀Th → ²³¹₉₁Pa + ?

From this equation, we see that the mass number is conserved but the atomic number is not.

The mass number is the superscript whereas the atomic number is the subscript.

Let's say the decay produces an emission of a particle denoted by X

²³¹₉₀Th → ²³¹₉₁Pa + ᵃₙX

What would the nature of X be?

For the charges and masses to be conserved, X must have mass number of 0 and an atomic number of -1.

Checking:

Mass number:

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Atomic number:

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With X having a mass number of 0 and an atomic number of -1, we have a beta particle emission. Specifically, a negatron has been emitted.

A negatron is denoted as ⁰₋₁β which perfectly makes the equation conserved and suits the description of X.

The complete equation is thus written as:

²³¹₉₀Th → ²³¹₉₁Pa + ⁰₋₁β + energy

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Brrunno [24]

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