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Alex Ar [27]
3 years ago
13

How many H atoms are in 6.43g x 10^24 molecules of water

Chemistry
1 answer:
kow [346]3 years ago
5 0

Answer:

12.86\times 10^{24} atoms of hydrogen

Explanation:

The molecular formula for a water molecule is H_2O.

From the above formula, we can conclude that 1 molecule of water contains 2 atoms of hydrogen and 1 atom of oxygen.

There are 6.43\times 10^{24} molecules of water.

1 molecule of water = 2 atoms of hydrogen.

∴ 6.43\times 10^{24} molecules of water = 2\times 6.43\times 10^{24}=12.86\times 10^{24} atoms of hydrogen.

Therefore, there are 12.86\times 10^{24} atoms of hydrogen in 6.43\times 10^{24} molecules of water.

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Rank the following salts in order of decreasing pH of their 0.1 M aqueous solutions.(a) FeCl2, FeCl3, MgCl2, KClO2 .(b) NH4Br, N
Firlakuza [10]

Answer:

a) FeCl2, FeCl3, MgCl2, KClO2.

KClO2 --> K+ + ClO2-; ClO2- will hydrolyse to form HClO +OH-

Mg+2, Fe+2 and Fe+3 ions will form acidic solutions, since theyfom slightly amount of

Mg+2 + 2H2O <-> Mg(OH)2 + 2H+

Fe+2 + 2H2O <-> Fe(OH)2 + 2H+

Fe+3 + 3H2O <-> Fe(OH)3 + 3H+

Therefore;

decreasing pH is high pH to low pH:

KClO2 > MgCl2 > FeCl2 > FeCl3

b) NH4Br, NaBrO2, NaBr, NaClO2.

NH4Br is acidic, forms NH4+ and NH4+ dnates H+ to form NH3 andH+

NaBrO2 is basic, forms Na+ + BrO2- then H2O + BrO2- HBrO2

NABr is neutral, NaClO2 is basics, forms Na+ + ClO2-then H2O + ClO2- HClO2

decreasig pH:

NaClO2 > NaBrO2 > NaBr >NH4Br

Note that HClO2 is stronger acid than HBrO2, therefore, expectmore HBrO2 formation

NaBrO2 > NaClO2 > NaBr >NH4Br

5 0
3 years ago
How many milliliters of a 0.215 molar solution are required to contain 0.0867 mol of NaBr
JulsSmile [24]

Answer: 403ml

Explanation:

M=\frac{mol}{L}

Solve for L;

L=\frac{mol}{M}\\L=\frac{0.0867mol}{0.215M}\\ L=0.403L

Convert to mililiters

0.403L(\frac{1000ml}{1L})=403ml

3 0
2 years ago
A good team member will actively listen, which means they will ______.
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B is the answer I think better sure
8 0
3 years ago
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A cough syrup contains 5.0% ethyl alcohol, c2h5oh, by mass. if the density of the solution is 0.9928 g/ml, determine the molarit
WARRIOR [948]
To answer the question above, let us a basis of the 1000 mL or 1 L. 
                 volume = (0.9928 g/mL)(1000mL) = 992.8 g
Then, determine the mass of the alcohol by multiplying the total mass by the decimal equivalent of 5%. 
               mass of alcohol = 0.05(992.8 g) = 49.64 g
Then, determine the number of moles of ethyl alcohol by dividing the mass of alcohol by the molar mass (46 g/mol). 
                       n = 49.64 g/ (46 g/mol) = 1.08 mol
Then, divide the number of moles by the volume (our basis is 1 L)
                       molarity = 1.08 mol/ 1 L = 1.08 M
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3 years ago
Balance N2 + H2 —NH3 what type of reaction
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