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wolverine [178]
1 year ago
14

A race car goes around a level, circular track with a diameter of 1.00 km at a constant speed of 95 km/h. What is the car's cent

ripetal acceleration in m/s2?answer in: m/s2
Physics
1 answer:
Andrews [41]1 year ago
6 0

To start, we need to know the formula for centripetal acceleration

a=\frac{v^2}{r}

In this problem, we know that the speed of the vehicle is 95 km/hr

We will need to convert that speed into m/s

95 km/hr = 26.3889 m/s

Second, we know that the diamater of the circular track is 1 km.

To find radius, we just take half of the diameter, which makes the radius 500 meters.

Now we have:

Velocity = 26.3889 m/s

& Radius = 500 meters

Plugging this into the centripetal acceleration formula yields us

a = (26.3889)^2/500 = 1.39 m/s^2

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Find the kenetic energy of a car of mass 700kg racing with a velocity of 10m/s
fiasKO [112]

Answer:

35000 KJ

Explanation:

The equation for the kinetic energy is given by the formula :

E_{k} = \frac{1}{2} mv^{2}

E_{k} = \frac{1}{2} (700)(10)^{2}

E_{k} = \frac{1}{2} (700)(100)

E_{k} = (350)(100)  OR E_{k} = \frac{1}{2} (70000)

E_{k} = 35000

Units will be kilojoules since the units of mass was kilograms .

Our final answer is 35000 KJ

Hope this helped and have a good day

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