To start, we need to know the formula for centripetal acceleration
In this problem, we know that the speed of the vehicle is 95 km/hr
We will need to convert that speed into m/s
95 km/hr = 26.3889 m/s
Second, we know that the diamater of the circular track is 1 km.
To find radius, we just take half of the diameter, which makes the radius 500 meters.
Now we have:
Velocity = 26.3889 m/s
& Radius = 500 meters
Plugging this into the centripetal acceleration formula yields us
a = (26.3889)^2/500 = 1.39 m/s^2
Answer:
°C
Explanation:
= mass of the horseshoe = 0.35 kg
= mass of the water = 1.40 L = 1.40 kg
= mass of the iron pot = 0.45 kg
= specific heat of iron = 450 J kg⁻¹ °C⁻¹
= specific heat of water = 4186 J kg⁻¹ °C⁻¹
= initial temperature of the horseshoe = ?
= initial temperature of the water = 22 °C
= initial temperature of the iron pot = 22 °C
= final temperature = 32 °C
Using conservation of Heat
°C