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wolverine [178]

1 year ago

14

A race car goes around a level, circular track with a diameter of 1.00 km at a constant speed of 95 km/h. What is the car's cent

ripetal acceleration in m/s2?answer in: m/s2

1 answer:

Andrews [41]1 year ago

6 0

To start, we need to know the formula for centripetal acceleration

$a=\frac{v^2}{r}$

In this problem, we know that the speed of the vehicle is 95 km/hr

We will need to convert that speed into m/s

95 km/hr = 26.3889 m/s

Second, we know that the diamater of the circular track is 1 km.

To find radius, we just take half of the diameter, which makes the radius 500 meters.

Now we have:

Velocity = 26.3889 m/s

& Radius = 500 meters

Plugging this into the centripetal acceleration formula yields us

a = (26.3889)^2/500 = 1.39 m/s^2

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4 years ago

You are working in cooperation with the Public Health department to design an electrostatic trap for particles from auto emissio

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3 years ago

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A chemical element is a species of atoms, including the pure substance made entirely of that species, that have a specific number of protons in their nuclei. Chemical elements, in contrast to chemical compounds, cannot be reduced by any chemical process into simpler molecules.

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2 years ago

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Marta_Voda [28]

Answer:

The angular velocity of the platform is 1.114 rad/s.

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Step 3: Calculate the initial angular momentum

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I = 21.1 * 1.63² = 56.06

Step 6: Total moment of inertia = 125.80 + 15.73 + 56.06 = 197.59

Step 7: Calculate final angular momentum = 197.59 * ω

197.59 * ω = 220.15

ω = 220.15 / 197.59

This is approximately 1.114 rad/s.

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3 years ago