A race car goes around a level, circular track with a diameter of 1.00 km at a constant speed of 95 km/h. What is the car's cent
1 answer:
To start, we need to know the formula for centripetal acceleration
In this problem, we know that the speed of the vehicle is 95 km/hr
We will need to convert that speed into m/s
95 km/hr = 26.3889 m/s
Second, we know that the diamater of the circular track is 1 km.
To find radius, we just take half of the diameter, which makes the radius 500 meters.
Now we have:
Velocity = 26.3889 m/s
& Radius = 500 meters
Plugging this into the centripetal acceleration formula yields us
a = (26.3889)^2/500 = 1.39 m/s^2
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Answer:
Explanation:
The force on the point charge q exerted by the rod can be found by Coulomb's Law.
Unfortunately, Coulomb's Law is valid for points charges only, and the rod is not a point charge.
In this case, we have to choose an infinitesimal portion on the rod, which is basically a point, and calculate the force exerted by this point, then integrate this small force (dF) over the entire rod.
We will choose an infinitesimal portion from a distance 'x' from the origin, and the length of this portion will be denoted as 'dx'. The charge of this small portion will be 'dq'.
Applying Coulomb's Law:
The direction of the force on 'q' is to the right, since both charges are positive, and they repel each other.
Now, we have to write 'dq' in term of the known quantities.
Now, substitute this into 'dF':
Now we can integrate dF over the rod.