A race car goes around a level, circular track with a diameter of 1.00 km at a constant speed of 95 km/h. What is the car's cent
1 answer:
To start, we need to know the formula for centripetal acceleration
In this problem, we know that the speed of the vehicle is 95 km/hr
We will need to convert that speed into m/s
95 km/hr = 26.3889 m/s
Second, we know that the diamater of the circular track is 1 km.
To find radius, we just take half of the diameter, which makes the radius 500 meters.
Now we have:
Velocity = 26.3889 m/s
& Radius = 500 meters
Plugging this into the centripetal acceleration formula yields us
a = (26.3889)^2/500 = 1.39 m/s^2
You might be interested in
Answer:
(i) 7.2 feet per minute.
(ii) No, the rate would be different.
(iii) The rate would be always positive.
(iv) the resultant change would be constant.
(v) 0 feet per min
Explanation:
Let the length of ladder is l, x be the height of the top of the ladder from the ground and y be the length of the bottom of the ladder from the wall,
By making the diagram of this situation,
Applying Pythagoras theorem,
Differentiating with respect to t ( time ),
( l = 26 feet = constant )
We have,
(i) From equation (1),
From equation (X),
(ii) From equation (X),
Thus, for different value of x the value of would be different.
(iii) Since, distance = Positive number,
So, the value of y will always a positive number.
Thus, from equation (X),
The rate would always be a positive.
(iv) The length of the ladder is constant, so, the resultant change would be constant.
i.e. x = increases ⇒ y = decreases
y = decreases ⇒ y = increases
(v) if ladder hit the ground x = 0,
So, from equation (X),
