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mars1129 [50]
1 year ago
6

1 5kg cat is lifted 2 m into the air.how much gpe does it gain?

Physics
1 answer:
____ [38]1 year ago
6 0

Answer:

<h3><em><u>Potential Energy= mgh = (5)(9.8)(2)= 98.</u></em></h3><h3 />
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These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the neg
Kay [80]

Answer:

Following are the solution to the given question:

Explanation:

For charging plates that are connected in a similar manner:

Calculating the total charge:

\to q =q_1 + q_2 = C_1V_1 +C_2V_2 =1320 + 2714 = 4034 \mu C

Calculating the common potential:

\to V = \frac{q}{C}= \frac{q}{(C_1 + C_2)} =\frac{4034}{6.8} = 593 \ V\\\\

Calculating the charge after redistribution:

When: \\\\q = q_{1}' + q_{2}' = q_1 + q_2        

\to q_{1}' = C_1V = 2.2 \times 593 = 1305\ \mu C\\  \\  \to               q_{2}' = C_2V = 4.6 \times 593 = 2729 \ \mu C

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3 years ago
How does pressure affect surface tension
tatyana61 [14]

the effect of pressure on surface tension can be attributed in part to absorption of gas at the surface of the liquid and in part to an intrinsic decrease in density of the liquid in the neighborhood of the surface.

In the case of liquids , Owing to contact forces between the edge of the surface and the vessel, the surface acquires a curvature, and if the liquid rises up at the edges where it meets the vessel, the pressure will be less in the liquid than in the air, for points just below and just above the surface. The vessel exerts an upward force on the liquid. This is simply a matter of looking at the directions of forces acting, knowing that the surface is under tension.

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Solve this question
Rudik [331]
Ok


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6 0
3 years ago
If you double the voltage in a circuit and reduce the resistance by a factor of four, what will happen to the current?
Kamila [148]
<span>doubling or tripling the voltage will cause the current to be doubled or tripled. On the other hand, any alteration in the resistance will result in the opposite or inverse alteration of the current. So doubling or tripling the resistance will cause the current to be one-half or one-third the original value.</span>
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A straight wire carries a current of 238 mA from right to left. What is the magnetic field at a point 10.0 cm directly below the
Alex777 [14]

Answer:

B = (4.76 × 10⁻⁷) T

Explanation:

From Biot Savart's law, the magnetic field formula is given as

B = (μ₀I)/(2πr)

B = magnetic field = ?

I = current = 238 mA = 0.238 A

μ₀ = magnetic constant = (4π × 10⁻⁷) H/m

r = 10 cm = 0.1 m

B = [4π × 10⁻⁷ × 0.238)/(2π×0.1)]

B = (4.76 × 10⁻⁷) T

The direction of the magnetic field is in the clockwise direction wrapped around the current-carrying wire.

Hope this Helps!!!

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