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ANTONII [103]
3 years ago
13

A 2.0 kg bird lands on a 1.0 x 10^1 kg bit of tree bark sitting on a frictionless ice-covered pond. The bird’s initial horizonta

l speed is 6.0 m/s. What is the final speed of the bird and bark?
Physics
1 answer:
Bond [772]3 years ago
7 0

Here in this type of question we can use momentum conservation

It is because we can see there is no external force on the system

So we can use momentum conservation principle

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

here we know that

m_1 = 2 kg

v_{1i} = 6 m/s

m_2 = 1 * 10^1 kg

v_{2i} = 0

now after bird sits on it then final speed of the both will be same

v_{2f} = v_{1f} = v m/s

2*6 + 1*10^1 * 0 = (2 + 1* 10^1) * v

12 = 12*v

v = 1 m/s

so final speed will be 1 m/s

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