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sladkih [1.3K]
3 years ago
13

What is an example of this picture

Physics
1 answer:
Natali [406]3 years ago
3 0
I don’t know but maybe is Thermal Energy
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B Minerals must be solid, have an orderly atomic structure, have a recognized chemical composition, be naturally occurring, and
zubka84 [21]

Answer:

Minerals must be solid, have an orderly atomic structure, have a recognized chemical composition, be naturally occurring and <u>inorganic in origin</u>.

Explanation:

6 0
4 years ago
Approximately what percent of the Moon’s surface is illuminated on a new-moon day? A) 0% B) 20% C) 50% D) 100%
Sergeeva-Olga [200]
At New Moon the percent illuminated is 0; at First and Last Quarters it is 50%; and at Full Moon it is 100%<span>. During the crescent phases the percent illuminated is between 0 and </span>50%<span> and during gibbous phases it is between </span>50%<span> and </span>100%<span>.
so it depends on the phase 


</span>
3 0
3 years ago
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Why are strokes and Alzheimer's disease serious conditions? Select all that apply. You can die from either one.
Sladkaya [172]
The first and fourth option my dudette
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3 years ago
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Newton's Law of Universal Gravitation states that the force F between two masses, m1 and m2, is given below, where G is a consta
Hitman42 [59]

Answer:

Explanation:

According to newton's law , force between mass m₁ and m₂ at distance x is given by the following expression

F = G m₁m₂ / x²

differentiating F with respect to x , we have

dF /  d x =  ₋2G m₁m₂ / x³ .

Rate of reduction  of force ∝  1 / x³

5 0
3 years ago
If a snowball melts so that its surface area decreases at a rate of 10 cm2/min, find the rate at which the diameter decreases wh
liubo4ka [24]

Answer: 4/9π

Explanation:

Surfacearea of snowball(SA) =4πr^2

dSA/dT = - 10cm^2/min

d = 9, hence, r = 9/2 = 4.5

Taking the derivative of surface area with respect to time:

dSA/dT = 8πrdr/dt

dSA/dT = - 10, r = 4.5

-10 = 8π(4.5)dr/dt

-10 = 36πdr/dt

Make dr/dt subject of the formula

dr/dt = - 10/36π

d = 2r

Differentiating d with respect to time, 't'

dd/dt = 2dr/dt

Therefore, 2dr/dt = 2*(dr/dt)

2×(- 10/36π) = - 20/36π

= -4/9π

Therefore, rate by which diameter decreases when diameter is 9cm is

4/9 π

7 0
3 years ago
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