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olga2289 [7]
3 years ago
11

A 328-kg car moving at 19.1 m/s in the + x direction hits from behind a second car moving at 13.0 m/s in the same direction. If

the second car has a mass of 790 kg and a speed of 15.1 m/s right after the collision, what is the velocity of the first car after this sudden collision?
Physics
1 answer:
Kisachek [45]3 years ago
8 0

Answer:

+14.0 m/s

Explanation:

we have mV + Mv = mU + Mu we solve for U = (mV + Mv - Mu)/m = (328*19.1 + 790*13 - 790*15.1)/328 = 14. Answer

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To increase the gravitational force between the two objects above, I could
egoroff_w [7]

Answer:

Option A

Explanation:

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Adding energy or increasing the speed of the particles at very low pressure in a solid would cause
weqwewe [10]
D. sublimation is correct



7 0
3 years ago
Which is true?
Andrew [12]

Answer:

e)  A changing magnetic field produces an electric field.

Explanation:

Ok, we start with a magnetic field and let's study how it affects the motion of a single electron. As the magnetic field changes, it will cause an electromotive force, that moves the electron, and because now we have a moving electron, now we will have an electric field. (Such that the direction of the electromotive force opposes the direction in which the magnetic field changes). This also can be deduced if we look at the third Maxwell's equation:

dE/dx = -dB/dt

This says that the spatial change in an electric field depends on how the magnetic field changes as time pass.

Then the correct option is e)  A changing magnetic field produces an electric field.

4 0
3 years ago
The pressure on a balloon holding 356 mL of an ideal gas is increased from 267 torr to 1.00 atm. What is the new volume of the b
Natalija [7]

Answer:

124.52 mL

Explanation:

from Boyle's Law,

PV = P'V' ................... Equation 1

Where P = Initial pressure of the gas, V = Initial volume of the gas, P' = Final pressure of the gas, V' = Final volume of the gas.

make V' the subject of the equation.

V' = PV/P'............. Equation 2

Given: P = 267 torr = (267×0.00131) = 0.34977 atm, V = 356 mL, P' = 1 atm

Substitute into equation 2

V' = (0.34977×356)/1

V' = 124.52 mL.

Hence the new volume of the balloon = 124.52 mL

4 0
3 years ago
A centrifuge rotor (hollow disk) is rotating at 10,000 rpm is shut off and brought to rest by a constant frictional torque of 1.
Y_Kistochka [10]

Answer:

The no of revolutions rotor turn before coming to rest is 1,601.1943 and time taken is equal to 19.21 seconds

Explanation:

here we know that torque = I×α

     α= angular acceleration

     I = moment of inertia of hollow disc = m×k^{2}

  given that m=4.37kg

                    k=0.0710m

           torque=1.2Nm

        w_{o}=10000\times \frac{\pi}{30} rad /s

         \alpha =\frac{torque}{I}

from the above equation we can calculate the angular acceleration of the hollow disc .

  since  w^{2}-w_o^{2} =2\alpha\theta

 from this above equation  \theta=\frac{w^{2}-w_{o}^{2}}{2\alpha }

   no of revolutions = \frac{\theta}{2\pi}  = 1,601.1943.

Now to calculate time we know that time = \frac{2\theta}{w+w_{o}}

   so upon calculating we will be getting t=19.21 seconds

5 0
3 years ago
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