Answer:
0.8 m
Explanation:
For "6 N" force :
F = magnitude of the force = 6 N
r = moment arm = 0.4 m
Torque due to "6 N" force is given as
τ = r F
τ = (0.4) (6)
τ = 2.4 Nm
For " 15 N" force :
F' = magnitude of the force = 15 N
r' = moment arm = ?
τ' = Torque = 5 τ = 5 x 2.4 = 12 Nm
Torque due to "15 N" force is given as
τ' = r' F'
12 = r' (15)
r' = 0.8 m
So the moment arm for "15 N" force is 0.8 m
The reading of the voltmeter can be determined by finding the potential difference across the 2Ω resistance by using the value of current in the circuit. V=IR, here V is the potential difference across a resistance R through which a current I is flowing.
Answer:
245 m
Explanation:
v = at + v₀
50.0 m/s = a (9.8 s) + 0 m/s
a = 5.10 m/s²
x = x₀ + v₀ t + ½ at²
x = 0 m + (0 m/s) (9.8 s) + ½ (5.10 m/s²) (9.8 s)²
x = 245 m
Since the temperature of the gas remains constant in the process, we can use Boyle's law, which states that for a gas transformation at constant temperature, the product between the gas pressure and its volume is constant:

which can also be rewritten as

(1)
where the labels 1 and 2 mark the initial and final conditions of the gas.
In our problem,

,

and

, so the final pressure of the gas can be found by re-arranging eq.(1):

Therefore the correct answer is
<span>1. 0.75 atm</span>