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jarptica [38.1K]
3 years ago
8

The first impression you give is the most important what does it mean?

Physics
1 answer:
Neko [114]3 years ago
3 0

Answer:

The reason why first impressions are so important is that they last well beyond that moment. This is thanks to something called the primacy effect, which means that when someone experiences something before other things in a sequence, they remember that first thing more.

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Calculate the mass of air in a room 5 m by 4 m by 3 m the density of air is 1.3 kg/m3
prohojiy [21]

Answer:

Explanation:

density (d) = 1.3 kg/m³

volume of the room (v)

= 5 m * 4m * 3 m

= 60 m³

mass(m) =?

now we know density is defined as mass per unit volume so

d = m / v

1.3 = m / 60

m = 78 kg

3 0
3 years ago
A capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has radius 10.5 cm,
Step2247 [10]

Answer:

U = 2.91 *10^{-5} J

Explanation:

energy density can be obtained as

U = \frac{1}{2}\epsilon_o E^{2}

Where,

E is electric field = \frac{kQ}{R^{2}}

K COLOUMB CONSTANT =8.99*10^{9} N -m2 /C2

Q is charge = CV

C is capacitance = 4\pi \epsilon_o \frac{r_1 r_2}{r_2 -r_1}

                             =4\pi *8.85*10^{-12} [\frac{10.5*16.5}{16.5 -10.5}]

                           = 3.21*10^{-9} F

Q = 3.21*10^{-9} *150 = 4.81*10^{-7] C

for r  = 10.6 cm

E = \frac{8.99*10^{9}*3.21*10^{-9}}{0.106^{2}}

E = 2568.34 N/C

U = \frac{1}{2}\epsilon_oE^{2}

U = \frac{1}{2}*8.85*10^{-12} *2568.34 ^2

U = 2.91 *10^{-5} J

8 0
3 years ago
The follow is an example of a mixture
Musya8 [376]

Answer:

Solutions, colloids and suspension.

4 0
4 years ago
at a certain instant an object is moving to the right with speed 1.0 m/s and has a constant acceleration to the left of 1.0 m/s^
chubhunter [2.5K]
For this problem, you would use the equation v=u+at. In this case, u=1 v=0 (when the object is at rest) a=-1
v=u+at
0=1+(-1)t
t=1 second
3 0
4 years ago
A sled starts from rest,
Marrrta [24]

Answer:

25.6 m/s

Explanation:

Draw a free body diagram of the sled.  There are two forces acting on the sled:

Normal force pushing perpendicular to the hill

Weight force pulling straight down

Take sum of the forces parallel to the hill:

∑F = ma

mg sin θ = ma

a = g sin θ

a = (9.8 m/s²) (sin 38.0°)

a = 6.03 m/s²

Given:

v₀ = 0 m/s

a = 6.03 m/s²

t = 4.24 s

Find: v

v = at + v₀

v = (6.03 m/s²) (4.24 s) + (0 m/s)

v = 25.6 m/s

5 0
3 years ago
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