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Yakvenalex [24]
1 year ago
14

this problem occurs in petroleum firefighting when fire streams are applied to the burning liquid surface at such an angle that

hot and / or burning oil is forced over the edge of the tank. the oil then flows down the side of the tank and you are now confronted with a fire on the ground as well as the one in the tank. this best defines which problem?
Physics
1 answer:
shutvik [7]1 year ago
7 0

Petroleum has less density than water. So, when fire streams are applied to the burning liquid surface at such an angle that hot and / or burning oil is forced over the edge of the tank, the oil then flows down the side of the tank and you are now confronted with a fire on the ground as well as the one in the tank.

<h3>What are the reasons not to use fire streams during deal with  burning oil?</h3>

When you spray water on a regular fire, you're attempting to lower the flame's temperature and contain the fire.

Fuel for an oil fire is oil. Temperature and oxidizer are present in a fire (oxygen). Due to the fact that oil is lighter than water, an explosion may result if it floats above water while water sinks beneath oil.

Consequently, water shouldn't be used to put out oil fires.

Learn more about density here:

brainly.com/question/15164682

#SPJ1

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balu736 [363]

Answer:

16.8 lb is the force on the brake pad of one wheel.

Explanation:

Force applied on the piston = F_1=5.6 lb

Area of the piston = A_1=0.6 inches^2

Force applied on the brakes = F_2

Area of the brakes = A_2=1.8 inches^2

Applying Pascal's law: 'For an incompressible fluid pressure at one surface is equal to the pressure at other surface'.

\frac{F_1}{A_2}=\frac{F_2}{A_2}

F_2=\frac{5.6 lb\times 1.8 inhes^2}{0.6 inches^2}=16.8 lb

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Answer:

Q = 169 BTU

Explanation:

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