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Yakvenalex [24]
1 year ago
14

this problem occurs in petroleum firefighting when fire streams are applied to the burning liquid surface at such an angle that

hot and / or burning oil is forced over the edge of the tank. the oil then flows down the side of the tank and you are now confronted with a fire on the ground as well as the one in the tank. this best defines which problem?
Physics
1 answer:
shutvik [7]1 year ago
7 0

Petroleum has less density than water. So, when fire streams are applied to the burning liquid surface at such an angle that hot and / or burning oil is forced over the edge of the tank, the oil then flows down the side of the tank and you are now confronted with a fire on the ground as well as the one in the tank.

<h3>What are the reasons not to use fire streams during deal with  burning oil?</h3>

When you spray water on a regular fire, you're attempting to lower the flame's temperature and contain the fire.

Fuel for an oil fire is oil. Temperature and oxidizer are present in a fire (oxygen). Due to the fact that oil is lighter than water, an explosion may result if it floats above water while water sinks beneath oil.

Consequently, water shouldn't be used to put out oil fires.

Learn more about density here:

brainly.com/question/15164682

#SPJ1

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What are factors within a region that affect or limit the physical environment?
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Answer:Some examples of limiting factors are biotic, like food, mates, and competition with other organisms for resources. Others are abiotic, like space, temperature, altitude, and amount of sunlight available in an environment. Limiting factors are usually expressed as a lack of a particular resource.

Explanation:hope this helps you

6 0
3 years ago
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Naily [24]

Answer:

50m/s, 187.5m

Explanation:

Consider unit analysis:

m/s² = m/(s×s)

This can be read as "meters per second, per second". From fundamental kinematics, meters per second is the same as saying velocity.

Velocity is being increased per second, and this is called acceleration:

a = v/t, where a is acceleration, v is change of velocity and t is change of time. "Change" is represented by a triangle called delta and (delta)A = A2 - A1

From the question, we have the variables:

a = 5m/s²

(delta)v = v2 - 25m/s

(delta)t = 5s (initial time is 0)

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The final velocity of the vehicle is 50m/s.

A formula exists to find displacement with regards to acceleration:

d=v(initial) × t +1/2 × a × t²

d=25m/s × 5s + 1/2 × 5m/s² ×(5s)²

d=125m+1/2×125m

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d=187.5m

The distance travelled by the vehicle is 192.5m.

<em>One of the most important skills you can have in any science is unit analysis. Treat meters, seconds, moles, etc as </em><em>values</em><em> when doing </em><em>calculations</em><em> </em><em>and see if you get the result you're looking for.</em>

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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

We know that,

  • force = mass \times acceleration

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  • m =  \dfrac{500}{20}

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Mass of skier is <u>25</u> kg

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