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MAVERICK [17]
3 years ago
8

Which formulas have been correctly rearranged to solve for radius? Check all that apply. r = GM central/v^2 r =fcm/v^2 r =ac/v^2

r =vt/2pi r =act/pi
Physics
2 answers:
jek_recluse [69]3 years ago
7 0

The orbital radius is: r=\frac{GM}{v^2}

Explanation:

The problem is asking to find the radius of the orbit of a satellite around a planet, given the orbital speed of the satellite.

For a satellite in orbit around a planet, the gravitational force provides the required centripetal force to keep it in circular motion, therefore we can write:

\frac{GMm}{r^2}=m\frac{v^2}{r}

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the satellite

r is the radius of the orbit

v is the speed of the satellite

Re-arranging the equation, we find:

\frac{GM}{r}=v^2\\r=\frac{GM}{v^2}

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

11Alexandr11 [23.1K]3 years ago
6 0

Answer:

a  and  d

Explanation:

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True is the anwser to your question
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3 years ago
Read 2 more answers
10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t
Mila [183]

Answer:

a. The thickness of the wire is 2.5 mm.

b. The wire is 0.25 cm thick.

Explanation:

Number of turns of the wire = 10

The length of total turns = 25 mm

a. The thickness of the wire can be determined by;

thickness of the wire = \frac{length of total turns}{number of turns}

                           = \frac{25}{10}

                           = 2.5 mm

Therefore, the wire is 2.5 mm thick.

b. To determine the thickness of the wire in centimetre;

10 mm = 1 cm

So that,

2.5 mm = x

x  = \frac{2.5}{10}

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The wire is 0.25 cm thick.

8 0
3 years ago
A certain 48 V electric forklift can lift up to 7000 lb at a
Gwar [14]

Answer:

256.25 A

Explanation:

7 0
2 years ago
A girl standing on a bridge throws a stone vertically downward with an initial velocity of 15.0 m/s into the river below. If the
hodyreva [135]
Vi = 15 m/s
t = 2 s
a = 9.8 m/s^2
y = ?

The kinematic equation that has all of our variables is d = Vi*t + 0.5*a*t^2
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6 0
3 years ago
A satellite is orbiting Earth in an approximately circular path. It completes one revolution each day (86,400 seconds). Its orbi
stira [4]
@AL2006 had answered this before: Well, first of all, wherever you got this question from has done 
a really poor job of question-writing.  There are a few assorted 
blunders in the question, both major and minor ones:

-- 22,500 is the altitude of a geosynchronous orbit in miles, not km.

-- That figure of 22,500 miles is its altitude above the surface, 
   not its radius from the center of the Earth. 

-- The orbital period of a synchronous satellite has to match 
    the period of the Earth's rotation, and that's NOT 24 hours.  
    It's about 3 minutes 56 seconds less ... about 86,164 seconds. 

Here's my solution to the question, using some of the wreckage 
as it's given, and correcting some of it.  If you turn in these answers
as homework, they'll be marked wrong, and you'll need to explain 
where they came from.  If that happens, well, serves ya right for
turning in somebody else's answers for homework.


The satellite is traveling a circle. The circle's radius is 26,200 miles
(not kilometers) from the center of the Earth, so its circumference 
is (2 pi) x (26,200 miles) = about 164,619 miles.

    Average speed = (distance covered) / (time to cover the distance)

                             = (164,619 miles) / day
                                (264,929 km)

                             =      6,859 miles per hour
                                  (11,039 km) 

                           =          1.91 miles per second
                                      (3.07 km)
6 0
3 years ago
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