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3 years ago

If you add air to a flat tire through a single small entry hole, why does the air spread out to fill the tire

2 answers:

7 0

The tire fills up just like any thing else that holds air when u pump a ball or tire up it fills all the way up cause it is a small confined space and after filling it with air the atoms of the air fill the tire up

mr Goodwill [35]3 years ago

5 0

Answer:

Explanation:

Air is made up of small particles which occupies all the place if filled in a close body.

A flat tire has a small nozzle to fill in air. As air pumped into it, it tends to spread itself into the complete tube.

This air gives shape to the rube making it perfectly circular. The particles of air have a greater inter molecular spacing and can acquire any shape.

This air given to the tire spread out in every part.

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When he sees teachers encouraging other children to wait in the cafeteria until the first bell rings, Ian follows them. What typ

Ostrovityanka [42]

This is observational learning because Ian observed that his peers waited in the cafeteria until the first bell rings. He decided to imitate them.

8 0

3 years ago

Read 2 more answers

The fastest measured pitched baseball left the pitcher's hand at a speed of 42.0 m/s. If the pitcher was in contact with the bal

I am Lyosha [343]

Answer:

The acceleration and time are 588 m/s² and 0.071 sec respectively.

Explanation:

Given that,

Speed = 42.0 m/s

Distance = 1.50 m

(a). We need to calculate the acceleration

Using equation of motion

$v^2=u^2+2as$

$a=\dfrac{v^2-u^2}{2s}$

Put the value in the equation

$a=\dfrac{42.0^2-0}{2\times1.50}$

$a=588\ m/s^2$

(b). We need to calculate the time

Using equation of motion

$v = u+at$

$t=\dfrac{v-u}{a}$

$t=\dfrac{42.0-0}{588}$

$t=0.071\ sec$

Hence, The acceleration and time are 588 m/s² and 0.071 sec respectively.

8 0

3 years ago

Extra CreditA particle is directed along the axis of the instrument in the gure. Aparallel plate capacitor sets up an electric e

kvv77 [185]

This question is incomplete, the complete question is;

A particle is directed along the axis of the instrument in the figure below. A parallel plate capacitor sets up an electric field E, which is oriented perpendicular to a uniform magnetic field B. If the plates are separated by d = 2.0 mm and the value of the magnetic field is B = 0.60T.

Calculate the potential difference, between the capacitor plates, required to allow a particle with speed v = 5.0 × 10⁵ m/s to pass straight through without deflection.

Answer:

the required potential difference, between the capacitor plates is 600 V

Explanation:

Given the data in the question;

B = 0.60 T

d = 2.0 mm = 0.002 m

v = 5.0 × 10⁵ m/s.

since particle pass straight through without deflection.

F $_{net$ = 0