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Dmitry_Shevchenko [17]
3 years ago
5

why the total mass of the products would be less than the total weight of the reactant after a chemical reaction?

Chemistry
1 answer:
Lisa [10]3 years ago
4 0
The best explanation would be that Gases were released during the Chemical reaction, causing a loss of Mass. 
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Which radioactive waste can be stored for decay and then safely released into the environment?
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The radioactive waste can be stored for decay and then safely released into the environment is N-16.

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Decays can be of three types: alpha, beta and gamma. Each of them corresponds to a different radioactive particle, which changes the nucleus of the emitting atom according to its characteristics.

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3 years ago
For some hypothetical metal the equilibrium number of vacancies at 750°C is 2.8 × 1024 m−3. If the density and atomic weight of
mash [69]

Answer:

The correct answer is 5.447 × 10⁻⁵ vacancies per atom.

Explanation:

Based on the given question, the at 750 degree C the number of vacancies or Nv is 2.8 × 10²⁴ m⁻³. The density of the metal is 5.60 g/cm³ or 5.60 × 10⁶ g/m³. The atomic weight of the metal given is 65.6 gram per mole. In order to determine the fraction of vacancies, the formula to be used is,  

Fv = Nv/N------ (i)  

Here Nv is the number of vacancies and N is the number of atomic sites per unit volume. To find N, the formula to be used is,  

N = NA×P/A, here NA is the Avogadro's number, which is equivalent to 6.022 × 10²³ atoms per mol, P is the density and A is the atomic weight. Now putting the values we get,  

N = 6.022 × 10²³ atoms/mol × 5.60 × 10⁶ g/m³ / 65.6 g/mol

N = 5.14073 × 10²⁸ atoms/m³

Now putting the values of Nv and N in the equation (i) we get,  

Fv = 2.8 × 10²⁴ m⁻³ / 5.14073 × 10²⁸ atoms/m^3

Fv = 5.44669 × 10⁻⁵ vacancies per atom or 5.447 × 10⁻⁵ vacancies/atom.  

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Determine the number of 3s electrons in Na .
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Answer:

Explanation:The atomic number of sodium is 11. That is, the number of electrons in sodium is 11. Therefore, a sodium atom will have two electrons in the first shell, eight in the 2nd orbit, and an electron in the 3rd shell.

3 0
1 year ago
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