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2 years ago

WHICH CHEMICAL EQUATION IS BALANCED? A.H2O--->H2+202 B.2H20--->2H2+02 C.2H20---->H2+202 D.H20--->2H2+202

2 answers:

7 0

A.
the left side - 2 atoms of hydrogen, 1 atom of oxygen
the right side - 2 atoms of hydrogen, 4 atoms of oxygen
not balanced

B.
the left side - 4 atoms of hydrogen, 2 atoms of oxygen
the right side - 4 atoms of hydrogen, 2 atoms of oxygen
balanced

C.
the left side - 4 atoms of hydrogen, 2 atoms of oxygen
the right side - 2 atoms of hydrogen, 4 atoms of oxygen
not balanced

D.
the left side - 2 atoms of hydrogen, 1 atom of oxygen
the right side - 4 atoms of hydrogen, 4 atoms of oxygen
not balanced

The answer is B.

Alchen [17]2 years ago

3 0

Answer:

answer B

Explanation:

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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the

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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

$\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}$

$P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}$

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

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