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3 years ago

WHICH CHEMICAL EQUATION IS BALANCED? A.H2O--->H2+202 B.2H20--->2H2+02 C.2H20---->H2+202 D.H20--->2H2+202

2 answers:

7 0

A.
the left side - 2 atoms of hydrogen, 1 atom of oxygen
the right side - 2 atoms of hydrogen, 4 atoms of oxygen
not balanced

B.
the left side - 4 atoms of hydrogen, 2 atoms of oxygen
the right side - 4 atoms of hydrogen, 2 atoms of oxygen
balanced

C.
the left side - 4 atoms of hydrogen, 2 atoms of oxygen
the right side - 2 atoms of hydrogen, 4 atoms of oxygen
not balanced

D.
the left side - 2 atoms of hydrogen, 1 atom of oxygen
the right side - 4 atoms of hydrogen, 4 atoms of oxygen
not balanced

The answer is B.

Alchen [17]3 years ago

3 0

Answer:

answer B

Explanation:

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If an equal number of moles of reactants are used, do the following equilibrium mixtures contain primarily reactants or products

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Answer:

For a: The equilibrium mixture contains primarily reactants.

For b: The equilibrium mixture contains primarily products.

Explanation:

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When $K_{eq}>1$ ; the reaction is product favored.
When $K_{eq}$ ; the reaction is reactant favored.
When $K_{e}=1$ ; the reaction is in equilibrium.

For the given chemical reactions:

For a:

The chemical equation follows:

$HCN(aq.)+H_2O(l)\rightleftharpoons CN^-(aq.)+H_3O^+(aq.);K_{eq}=6.2\times 10^{-10}$

The expression of $K_{eq}$ for above reaction follows:

$K_{eq}=\frac{[CN^-][H_3O^+]}{[HCN][H_2O]}=6.2\times 10^{-10}$

As, $K_{eq}$ , the reaction will be favored on the reactant side.

Hence, the equilibrium mixture contains primarily reactants.

For b:

The chemical equation follows:

$H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g);K_{eq}=2.51\times 10^{4}$

The expression of $K_{eq}$ for above reaction follows:

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3 years ago

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Hence, the correct answer is absorbed.

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Determine a massa, em kg, de um material que está contida em um volume de 18L. Sabe-se que a densidade do material é de 0,9 g/cm

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The question in English is "Determine the mass, in kg, of a material that is contained in a volume of 18L. It is known that the material density is 0.9 g/cm 3"

Answer:

We can use a simple equation to solve this problem. 
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Where d is the density, m is the mass and v is the volume.

d = 0.9 g/cm³
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By applying the equation,
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2 years ago