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brilliants [131]
3 years ago
10

WHICH CHEMICAL EQUATION IS BALANCED? A.H2O--->H2+202 B.2H20--->2H2+02 C.2H20---->H2+202 D.H20--->2H2+202

Chemistry
2 answers:
NeX [460]3 years ago
7 0
A.
the left side - 2 atoms of hydrogen, 1 atom of oxygen
the right side - 2 atoms of hydrogen, 4 atoms of oxygen
not balanced

B.
the left side - 4 atoms of hydrogen, 2 atoms of oxygen
the right side - 4 atoms of hydrogen, 2 atoms of oxygen
balanced

C.
the left side - 4 atoms of hydrogen, 2 atoms of oxygen
the right side - 2 atoms of hydrogen, 4 atoms of oxygen
not balanced

D.
the left side - 2 atoms of hydrogen, 1 atom of oxygen
the right side - 4 atoms of hydrogen, 4 atoms of oxygen
not balanced

The answer is B.
Alchen [17]3 years ago
3 0

Answer:

answer B

Explanation:

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A 1.775g sample mixture of potassium hydrogen carbonate is decomposed by heating. if the mass loss is 0.275g what is the percent
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A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

  • Step 1: Write the balanced equation for the decomposition of KHCO₃.

2 KHCO₃(s) → K₂CO₃(s) + CO₂(g) + H₂O(l)

The mass loss of 0.275 g is due to the gaseous CO₂ that escapes the sample.

  • Step 2: Calculate the mass of KHCO₃ that formed 0.275 g of CO₂.

In the balanced equation, the mass ratio of KHCO₃ to CO₂ is 200.24:44.01.

0.275 g CO₂ × 200.24 g KHCO₃/44.01 g CO₂ = 1.25 g KHCO₃

  • Step 3: Calculate the mass percentage of KHCO₃ in the sample.

There are 1.25 g of KHCO₃ in the 1.775 g sample.

%KHCO₃ = 1.25 g/1.775 g × 100% = 70.4%

A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.

Learn more about decomposition reactions here: brainly.com/question/14219426

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What is the difference between acute and chronic radiation poisoning
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A 0.15 M NaOH solution has a volume of 0.125 L but is then diluted to 0.15 L. What is the concentration of the new solution
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Answer:

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Explanation:

.15 M/L   * .125 L = .01875 moles

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.01875M / (150/1000) = .125M

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Scientists in a lab are working with two different samples of the element mercury. They know that the different samples are diff
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Answer:

the mass number

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